Compute square root to 1 decimal

## Problem Given a non-negative real number `x`, implement a function `sqrt1dp(x)` that returns \(\sqrt{x}\) rounded (or truncated—clarify with interviewer) to **one digit after the decimal point**. ### Requirements - Do **not** call a built-in square root function. - Your answer must be accurate to **1 decimal place** (e.g., error < 0.05 if rounding). - Discuss how you would **optimize** the algorithm (time complexity and convergence). ### Examples - `x = 2` → `1.4` - `x = 9` → `3.0` - `x = 0` → `0.0` ### Clarifications to ask - Rounding vs truncation to 1 decimal. - Input range (e.g., up to 1e9?) and whether `x` can be non-integer. - Acceptable error tolerance if not using decimal formatting.