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This question evaluates a candidate's understanding of numerical methods for root finding, floating-point precision control, and algorithmic time complexity analysis when computing square roots without built-in functions.

  • hard
  • Bytedance
  • Coding & Algorithms
  • Software Engineer

Compute square root with precision

Company: Bytedance

Role: Software Engineer

Category: Coding & Algorithms

Difficulty: hard

Interview Round: Onsite

Given a non-negative integer `val` and a non-negative integer `precise`, compute the square root of `val` without using any built-in square-root function. Return a result whose absolute error is at most `10^-precise`. Also explain the time complexity of your approach.

Quick Answer: This question evaluates a candidate's understanding of numerical methods for root finding, floating-point precision control, and algorithmic time complexity analysis when computing square roots without built-in functions.

Given two non-negative integers `val` and `precise`, compute the square root of `val` without using any built-in square-root operation. Return the result truncated to exactly `precise` digits after the decimal point as a float. This guarantees that the absolute error is less than `10^-precise`. Be prepared to explain the time complexity of your approach.

Constraints

  • 0 <= val <= 10^12
  • 0 <= precise <= 6
  • Do not use any built-in square-root function

Examples

Input: (10, 3)

Expected Output: 3.162

Explanation: `sqrt(10) ≈ 3.162277...`, and truncating to 3 decimal places gives `3.162`.

Input: (2, 5)

Expected Output: 1.41421

Explanation: `sqrt(2) ≈ 1.414213...`, and truncating to 5 decimal places gives `1.41421`.

Input: (0, 4)

Expected Output: 0.0

Explanation: The square root of 0 is exactly 0, regardless of the requested precision.

Input: (27, 0)

Expected Output: 5.0

Explanation: `sqrt(27) ≈ 5.196...`, and truncating to 0 decimal places gives `5.0`.

Input: (99980001, 4)

Expected Output: 9999.0

Explanation: `99980001 = 9999^2`, so the square root is exactly `9999`.

Hints

  1. Binary search works because if `x*x <= val`, then every number smaller than `x` also satisfies the condition.
  2. To avoid floating-point precision issues, scale the problem: finding `sqrt(val)` to `precise` decimal places is equivalent to finding the integer square root of `val * 10^(2 * precise)`.
Last updated: May 4, 2026

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