Find largest digit-sum bucket size
Company: Roblox
Role: Software Engineer
Category: Coding & Algorithms
Difficulty: Medium
Interview Round: Technical Screen
Quick Answer: This question evaluates a candidate's competency in combinatorial counting, digit-sum properties, and algorithmic optimization for range queries within the Coding & Algorithms domain.
Constraints
- 1 <= low <= high <= 10^5 (iteration over the range is feasible at this scale)
- s(x) is the sum of the base-10 digits of x
- The answer is the maximum bucket size; ties resolve to the same common size
Examples
Input: (1, 10)
Expected Output: 2
Explanation: Digit sums 1..9 then 1 again for 10; bucket for sum 1 = {1,10} has size 2, the max.
Input: (5, 15)
Expected Output: 2
Explanation: Sum 6 = {6, 15} and sum 5 = {5, 14} each have size 2; max bucket size is 2.
Input: (19, 28)
Expected Output: 2
Explanation: Sums: 19->10, 20->2, 21->3, 22->4, 23->5, 24->6, 25->7, 26->8, 27->9, 28->10; bucket for sum 10 = {19,28} has size 2.
Input: (7, 7)
Expected Output: 1
Explanation: Single element; its bucket (sum 7) has size 1.
Input: (1, 100)
Expected Output: 10
Explanation: The most populated digit-sum bucket over 1..100 holds 10 numbers.
Input: (100, 110)
Expected Output: 2
Explanation: Crossing a hundreds boundary; the largest shared-digit-sum bucket has size 2 (e.g. sum 1 = {100, 110}).
Hints
- Compute the digit sum of each number by repeatedly taking x % 10 and x //= 10.
- Use a hash map keyed by digit sum to count how many numbers fall in each bucket, tracking the running maximum.
- For the large-range follow-up, think about counting numbers with a given digit sum using digit DP instead of enumerating every x: count(high, target) - count(low - 1, target).