Compute maximum concurrent trips from intervals
Company: Uber
Role: Data Scientist
Category: Coding & Algorithms
Difficulty: medium
Interview Round: Technical Screen
Quick Answer: This question evaluates a candidate's skill in designing efficient algorithms for interval overlap counting, including event ordering, handling half-open interval edge cases, and reasoning about concurrent activity timing.
Part 1: Maximum Concurrent Trips and Earliest Time
Constraints
- 0 <= n <= 10^5
- 0 <= start < end <= 10^9
- Intervals are half-open: [start, end)
- If end == start for two trips, they do not overlap
- An O(n log n) time solution is expected
Examples
Input: [[0, 10], [5, 12], [11, 13], [2, 7]]
Expected Output: (3, 5)
Explanation: The maximum overlap is 3, first reached at time 5.
Input: [[1, 3], [3, 5]]
Expected Output: (1, 1)
Explanation: The intervals touch at 3 but do not overlap, so the maximum is 1.
Hints
- Sort all start times and end times separately, then sweep through them with two pointers.
- Because the intervals are half-open, when a start time equals an end time, process the end first.
Part 2: Earliest Continuous Range of Maximum Concurrency
Constraints
- 0 <= n <= 10^5
- 0 <= start < end <= 10^9
- Intervals are half-open: [start, end)
- If end == start for two trips, they do not overlap
- An O(n log n) time solution is expected
Examples
Input: [[0, 10], [5, 12], [11, 13], [2, 7]]
Expected Output: (3, 5, 7)
Explanation: The concurrency is 3 for the continuous range [5, 7).
Input: [[0, 2], [1, 3], [4, 6], [5, 7]]
Expected Output: (2, 1, 2)
Explanation: Maximum concurrency 2 happens on [1, 2) and [5, 6), so return the earliest one.
Hints
- The active-trip count only changes at interval boundaries, so sweep across sorted unique event times.
- Aggregate all changes at the same timestamp; if a trip ends and another starts at the same time, the maximum range may continue without a break.
Part 3: Maximum Concurrent Trips in a Start-Sorted Stream
Constraints
- 0 <= n <= 10^5
- 0 <= start < end <= 10^9
- Intervals are half-open: [start, end)
- The input is sorted by nondecreasing start time
- Use only O(k) extra space, where k is the number of active trips
Examples
Input: [[0, 10], [2, 7], [5, 12], [11, 13]]
Expected Output: (3, 5)
Explanation: The maximum number of active trips is 3, first reached when the trip starting at 5 arrives.
Input: []
Expected Output: (0, None)
Explanation: No trips means no concurrency.
Hints
- Keep the end times of currently active trips in a min-heap.
- Before adding a new trip [s, e), remove every active trip with end <= s, because touching intervals do not overlap.