Design a least-recently-used cache
Company: Ambience Healthcare
Role: Software Engineer
Category: Coding & Algorithms
Difficulty: Medium
Interview Round: Technical Screen
Design and implement a least-recently-used (LRU) cache with a fixed capacity. Support get(key) -> value and put(key, value) in average O(
1) time. When the cache is full, evict the least recently used entry. Explain your choice of data structures, detail how you update recency on reads and writes, and describe how you handle updates to existing keys, missing keys, and capacity edge cases (e.g., capacity =
0). Analyze time and space complexity.
Quick Answer: Design a least-recently-used cache evaluates algorithm design, data structures, correctness, complexity, edge cases, and implementation details in a realistic interview setting. A strong answer states assumptions, handles edge cases, explains trade-offs, and shows how to validate the result clearly.
Solution
# Solution Alignment
The prompt asks for an implementation-level answer. The safest way to present it is to define the state, maintain clear invariants, then walk through complexity and tests.
## Problem Restatement
Design and implement a least-recently-used (LRU) cache with a fixed capacity. Support get(key) -> value and put(key, value) in average O( 1) time. When the cache is full, evict the least recently used entry. Explain your choice of data structures, detail how you update recency on reads and writes, and describe how you handle updates to existing keys, missing keys, and capacity edge cases (e.g., capacity = 0). Analyze time and space complexity.
## Recommended Approach
Use a hash map from key to doubly linked-list node plus a doubly linked list ordered by recency. get moves the node to the front. put updates and moves an existing node, or inserts a new node at the front and evicts the tail when capacity is exceeded.
## Correctness
The implementation should maintain an invariant after each loop or operation that directly matches the problem statement. At termination, that invariant implies the returned value has considered every valid candidate exactly once, or has preserved the required data-structure state after every API call.
## Complexity
get and put are O(1) average time. Space is O(capacity).
## Edge Cases and Tests
Capacity 0 or 1, updating an existing key, eviction order after get, repeated puts, and missing-key gets.