Solve a child-sampled probability puzzle by correcting size-biased sampling. The answer converts school survey child proportions into household proportions and shows why the probability a random household has one child is 5/7, not 50%.
You survey 100 children at a school and ask how many children are in their family. The responses are:
- 50 children say their family has 1 child.
- 20 children say their family has 2 children.
- 30 children say their family has 3 children.
Now you go to a random house in the same town and ask how many children live there. Assuming the school sample is representative and family sizes larger than 3 do not occur, estimate the probability that the randomly chosen house has exactly 1 child.
### Constraints & Assumptions
- The school survey samples children, not households.
- Larger families are more likely to appear in the school sample because they contribute more children.
- Assume 1-, 2-, and 3-child households are the only possibilities.
- Explain the sampling bias and do not simply use 50%.
### Clarifying Questions to Ask
- Are we sampling a random child or a random household in the final question?
- Are all children in the town equally likely to attend the sampled school?
- Are households with more than 3 children impossible or just unobserved?
- Are we ignoring households with zero children?
### Part 1 - Identify The Sampling Bias
Why is the school survey not a direct estimate of household probabilities?
#### What This Part Should Cover
- Child-sampled proportions versus household-sampled proportions.
- Size-biased sampling: a 3-child family contributes three children to the school sample.
### Part 2 - Convert Child Proportions To Household Proportions
How do you estimate the household distribution?
#### What This Part Should Cover
- Let `r_k` be the probability a random child comes from a `k`-child household.
- Let `q_k` be the probability a random household has `k` children.
- Use `q_k` proportional to `r_k / k`, then normalize.
### Part 3 - Compute The Final Probability
What is the probability that a random house has exactly 1 child?
#### What This Part Should Cover
- Computation using either proportions or implied family counts.
- Final answer of `5/7`, approximately `71.4%`.
### What a Strong Answer Covers
- Recognizes size-biased sampling immediately.
- Correctly converts from child-level to household-level probabilities.
- Explains why the intuitive 50% answer is wrong.
- States assumptions about zero-child and larger-than-3-child households.
### Follow-up Questions
- How would the answer change if households with zero children were included?
- What if family sizes larger than 3 exist but were not observed?
- What is the general formula for any maximum family size?
- How would uncertainty from only 100 surveyed children affect the estimate?
Quick Answer: Solve a child-sampled probability puzzle by correcting size-biased sampling. The answer converts school survey child proportions into household proportions and shows why the probability a random household has one child is 5/7, not 50%.
mediumData ScientistTechnical ScreenStatistics & Math
6
0
You survey 100 children at a school and ask how many children are in their family. The responses are:
50 children say their family has 1 child.
20 children say their family has 2 children.
30 children say their family has 3 children.
Now you go to a random house in the same town and ask how many children live there. Assuming the school sample is representative and family sizes larger than 3 do not occur, estimate the probability that the randomly chosen house has exactly 1 child.
Constraints & Assumptions
The school survey samples children, not households.
Larger families are more likely to appear in the school sample because they contribute more children.
Assume 1-, 2-, and 3-child households are the only possibilities.
Explain the sampling bias and do not simply use 50%.
Clarifying Questions to Ask Guidance
Are we sampling a random child or a random household in the final question?
Are all children in the town equally likely to attend the sampled school?
Are households with more than 3 children impossible or just unobserved?
Are we ignoring households with zero children?
Part 1 - Identify The Sampling Bias
Why is the school survey not a direct estimate of household probabilities?
What This Part Should Cover Guidance
Child-sampled proportions versus household-sampled proportions.
Size-biased sampling: a 3-child family contributes three children to the school sample.
Part 2 - Convert Child Proportions To Household Proportions
How do you estimate the household distribution?
What This Part Should Cover Guidance
Let
r_k
be the probability a random child comes from a
k
-child household.
Let
q_k
be the probability a random household has
k
children.
Use
q_k
proportional to
r_k / k
, then normalize.
Part 3 - Compute The Final Probability
What is the probability that a random house has exactly 1 child?
What This Part Should Cover Guidance
Computation using either proportions or implied family counts.
Final answer of
5/7
, approximately
71.4%
.
What a Strong Answer Covers Guidance
Recognizes size-biased sampling immediately.
Correctly converts from child-level to household-level probabilities.
Explains why the intuitive 50% answer is wrong.
States assumptions about zero-child and larger-than-3-child households.
Follow-up Questions Guidance
How would the answer change if households with zero children were included?
What if family sizes larger than 3 exist but were not observed?
What is the general formula for any maximum family size?
How would uncertainty from only 100 surveyed children affect the estimate?