Evaluates derivation of correlation from variance identities for two random variables. Strong answers explain why Var(X+Y) and Var(X) alone do not identify correlation, then derive covariance and correlation when Var(Y) is also known.
# Deriving Correlation from Variances
You have two random variables X and Y with finite second moments. You are given Var(X + Y) and Var(X).
Answer the questions below.
### Constraints & Assumptions
- All variances are computed under the same probability model.
- Variances are finite.
- Correlation is defined only when Var(X) and Var(Y) are positive.
- Show the variance identity used in the derivation.
### Clarifying Questions to Ask
- Is Var(Y) known?
- Are X and Y non-degenerate?
- Are we assuming independence, or should covariance be inferred?
- Are these population variances or sample estimates?
### Part 1 - Identifiability
Is Corr(X, Y) identifiable from only Var(X + Y) and Var(X)? Explain why or why not.
#### What This Part Should Cover
- Use Var(X + Y) = Var(X) + Var(Y) + 2 Cov(X, Y).
- Explain that Var(Y) and Cov(X, Y) are both unknown.
- State that one equation with two unknowns does not identify correlation.
- Note that covariance must be normalized by both standard deviations.
### Part 2 - Derivation with Var(Y)
If Var(Y) is also given, derive Corr(X, Y) in terms of Var(X + Y), Var(X), and Var(Y).
#### What This Part Should Cover
- Rearrange the variance identity to get Cov(X, Y) = [Var(X + Y) - Var(X) - Var(Y)] / 2.
- Divide by sqrt(Var(X) Var(Y)).
- Provide the final formula for correlation.
- Mention valid inputs must produce a correlation in [-1, 1].
### Follow-up Questions
- How would the formula change for Var(X - Y)?
- What if Var(Y) = 0?
- How would sampling error affect an estimated correlation from sample variances?
Quick Answer: Evaluates derivation of correlation from variance identities for two random variables. Strong answers explain why Var(X+Y) and Var(X) alone do not identify correlation, then derive covariance and correlation when Var(Y) is also known.