Prove Equal Probability Impossible with Relabeled Dice Faces
Quick Overview
This interview question evaluates statistical assumptions, formulas, estimation strategy, uncertainty, edge cases, and interpretation in a realistic interview setting. A strong answer for Prove Equal Probability Impossible with Relabeled Dice Faces states assumptions, handles edge cases, explains trade-offs, and shows how to validate the result clearly.
Prove Equal Probability Impossible with Relabeled Dice Faces
Company: Yahoo
Role: Data Scientist
Category: Statistics & Math
Difficulty: medium
Interview Round: Technical Screen
##### Scenario
Interview assessing candidate's understanding of probability distributions with a dice-configuration puzzle used by a gaming analytics team.
##### Question
You have two fair six-sided dice. Can you relabel or configure the faces so that when both dice are rolled, the sums 1 through 12 each appear with equal probability? If yes, provide the new face labels; if no, give a rigorous proof of impossibility.
##### Hints
Equal probability requires each of the 12 sums to occur exactly 3 times out of 36. Analyze face-pair counts and parity constraints.
Quick Answer: This interview question evaluates statistical assumptions, formulas, estimation strategy, uncertainty, edge cases, and interpretation in a realistic interview setting. A strong answer for Prove Equal Probability Impossible with Relabeled Dice Faces states assumptions, handles edge cases, explains trade-offs, and shows how to validate the result clearly.
Prove Equal Probability Impossible with Relabeled Dice Faces
Yahoo
Aug 4, 2025, 10:55 AM
mediumData ScientistTechnical ScreenStatistics & Math
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Prove Equal Probability Impossible with Relabeled Dice Faces
Uniform Sums from Two Relabeled Fair Dice
Setup
You have two fair six-sided dice. You may relabel each die's faces with integers; duplicates are allowed. Each face on a given die is equally likely to appear on a roll.
Task
Can you relabel the faces so that when both dice are rolled, each sum from 1 through 12 occurs with equal probability? If yes, give one valid labeling (for both dice). If no, provide a rigorous proof of impossibility.
Equal probability over 36 outcomes means each sum 1–12 must occur exactly 3 times.
You may use parity and face-pair counting arguments.
Hints
Each of the 12 sums must occur exactly 3 out of 36 outcomes.
Think about extreme sums (1 and 12) and parity of face labels.
A generating-function or modular (mod 3) argument can greatly constrain possible face multiplicities.
Constraints & Assumptions
Preserve the scope, facts, inputs, and requested outputs from the prompt above.
If the prompt leaves a detail unspecified, state a reasonable assumption before relying on it.
Keep the answer interview-ready: concise enough to present, but concrete enough to implement or evaluate.
Clarifying Questions to Ask Guidance
Clarify the random variables, distributional assumptions, independence assumptions, and desired output.
Show enough derivation for the interviewer to follow the reasoning.
Explain how you would validate the result with simulation or sensitivity checks.
What a Strong Answer Covers Guidance
A correct setup with definitions, formulas, and boundary conditions.
A step-by-step derivation or estimation plan.
Interpretation of the result, including uncertainty and practical limitations.
Checks for assumptions, edge cases, and numerical stability.
Follow-up Questions Guidance
How would the result change if the assumptions were relaxed?
Can you verify the answer with a simulation?
What is the most likely source of estimation error?