Quick Overview

This question evaluates proficiency in Python data manipulation and pandas DataFrame construction, specifically handling nested list structures and aligning rows by identifiers.

Convert Dictionary to DataFrame

Company: Walmart Labs

Role: Data Scientist

Category: Data Manipulation (SQL/Python)

Difficulty: hard

Interview Round: Technical Screen

Using Python and pandas, convert the following dictionary into a DataFrame. Each top-level key is a target column name, and each value is a list of `[row_id, cell_value]` pairs. Use the first element of each pair as the row identifier, align rows by `row_id` across all keys, and produce a wide DataFrame with one row per `row_id` and one column per top-level key. Input: ```python data = { 'text1': [[123, '2'], [345, '3']], 'text2': [[123, '4'], [345, '4']] } ``` Expected structure: - `row_id = 123` -> `text1 = '2'`, `text2 = '4'` - `row_id = 345` -> `text1 = '3'`, `text2 = '4'` Write Python code to create the DataFrame.

Overview: This question evaluates proficiency in Python data manipulation and pandas DataFrame construction, specifically handling nested list structures and aligning rows by identifiers.

Given a key-value style table kv_cells with columns (key_name, row_id, cell_value), pivot the data to produce one row per row_id and one column per key_name (text1, text2).

Tables

kv_cells(key_name VARCHAR, row_id INTEGER, cell_value VARCHAR)

Hints

  1. Use conditional aggregation with CASE expressions to pivot key_name values into columns.
  2. GROUP BY row_id and compute each target column with MAX(CASE WHEN key_name = 'textX' THEN cell_value END).

Loading coding console...