Explain strings, moves, and concurrency
Company: xAI
Role: Software Engineer
Category: Coding & Algorithms
Difficulty: Medium
Interview Round: Technical Screen
Quick Answer: This question evaluates understanding of string data structures, ownership and move semantics (including Rust-specific move behavior), and concurrency models such as threads versus asynchronous coroutines, testing competencies in memory management, performance analysis, and concurrent programming.
Constraints
- 1 <= len(ops) <= 200000
- Variable names match [A-Za-z_][A-Za-z0-9_]*
- 0 <= n <= 10^9 for new x n
- mconcat x y z will have x distinct from y and z
- All reads reference variables that have been defined earlier
- Sum of all referenced lengths can be up to 10^12; use 64-bit or big integers
- Process should be O(len(ops)) time and O(U) space where U is number of variables
Solution
def total_copy_cost(ops: list[str]) -> int:
store: dict[str, int] = {}
total = 0
for line in ops:
parts = line.strip().split()
if not parts:
continue
op = parts[0]
if op == 'new':
if len(parts) != 3:
raise ValueError('Invalid new operation format')
x = parts[1]
n = int(parts[2])
store[x] = n
total += n
elif op == 'copy':
if len(parts) != 3:
raise ValueError('Invalid copy operation format')
x, y = parts[1], parts[2]
length = store[y]
store[x] = length
total += length
elif op == 'move':
if len(parts) != 3:
raise ValueError('Invalid move operation format')
x, y = parts[1], parts[2]
if x != y:
length = store[y]
store[x] = length
store[y] = 0
# cost 0
elif op == 'concat':
if len(parts) != 4:
raise ValueError('Invalid concat operation format')
x, y, z = parts[1], parts[2], parts[3]
ly, lz = store[y], store[z]
store[x] = ly + lz
total += ly + lz
elif op == 'mconcat':
if len(parts) != 4:
raise ValueError('Invalid mconcat operation format')
x, y, z = parts[1], parts[2], parts[3]
# By constraint, x is distinct from y and z
ly, lz = store[y], store[z]
store[x] = ly + lz
store[y] = 0
store[z] = 0
# cost 0
else:
raise ValueError('Unknown operation: ' + op)
return total
Explanation
Time complexity: O(n), where n is the number of operations. Space complexity: O(u), where u is the number of distinct variables.
Hints
- Track only lengths, not string contents.
- Use a dictionary mapping variable names to current lengths.
- copy and concat add the source lengths to the total cost.
- move sets the destination length and empties the source with zero cost.
- mconcat sets destination to sum of source lengths and empties both sources with zero cost.