## Problem You are given `n` people labeled `0` to `n-1` at a party. You can call an API: - `knows(a, b) -> bool`: returns `true` if person `a` knows person `b`, otherwise `false`. A **special person** is defined as someone who: 1. Is **known by everyone else** (for all `i != x`, `knows(i, x) == true`), and 2. **Knows nobody else** (for all `i != x`, `knows(x, i) == false`). Return the label of the special person if one exists, otherwise return `-1`. ## Constraints - `1 <= n <= 10^4` - You should minimize the number of API calls; aim for **O(n)** calls. ## Notes - `knows(a, a)` is undefined and should not be relied upon.