Quick Overview

This question evaluates the ability to analyze arrays for the largest subset sharing a common digit, emphasizing digit-level feature extraction, frequency analysis, and set-based reasoning. Commonly asked in the Coding & Algorithms domain, it assesses practical algorithmic implementation and efficient aggregation/counting with basic data structures rather than purely conceptual reasoning.

Find largest subset sharing a common digit

Company: Google

Role: Software Engineer

Category: Coding & Algorithms

Difficulty: easy

Interview Round: Take-home Project

You are given a list `A` of **two-digit integers** (each from 10 to 99). Two integers are said to “share a digit” if they have at least one digit in common (e.g., `23` and `35` share digit `3`). Determine the **maximum size of a subset** of `A` such that **all numbers in the subset share at least one common digit** (i.e., there exists a digit `d` in `{0,1,...,9}` that appears in every number in the chosen subset). **Input:** Array/list `A` of length `m`, with each `A[i]` in `[10, 99]`. **Output:** An integer = the maximum possible subset size. **Example:** - `A = [23, 35, 30, 19]` - The digit `3` appears in `23, 35, 30` → answer is `3`.

Quick Answer: This question evaluates the ability to analyze arrays for the largest subset sharing a common digit, emphasizing digit-level feature extraction, frequency analysis, and set-based reasoning. Commonly asked in the Coding & Algorithms domain, it assesses practical algorithmic implementation and efficient aggregation/counting with basic data structures rather than purely conceptual reasoning.

Given two-digit integers, return the largest number of elements that all contain one common digit.

Constraints

  • Numbers are two-digit integers in normal inputs

Examples

Input: ([11, 21, 31, 41, 16, 17, 18, 34, 57],)

Expected Output: 7

Input: ([23, 35, 30, 19],)

Expected Output: 3

Hints

  1. Count how many numbers contain each digit, counting a number once per digit even if repeated.

Loading coding console...