Quick Overview

This question evaluates proficiency with relational aggregation and join operations for counting related records across tables. It is commonly asked to assess understanding of SQL joins and grouping within the Data Manipulation (SQL/Python) domain and tests practical application of handling absent relationships rather than purely conceptual theory.

List Departments with Student Counts Including Zero

Company: Point72

Role: Data Scientist

Category: Data Manipulation (SQL/Python)

Difficulty: medium

Interview Round: Technical Screen

Students +----+--------+---------+ | id | name | dept_id | +----+--------+---------+ | 1 | Alice | 1 | | 2 | Bob | 2 | | 3 | Carol | 1 | +----+--------+---------+ ​ Departments +----+------------+ | id | dept_name | +----+------------+ | 1 | CS | | 2 | Math | | 3 | Physics | +----+------------+ ##### Scenario University dashboard must display every department and how many students it currently has, including departments with zero students. ##### Question Write a SQL query that lists each department name and the corresponding student count. Departments with no students should appear with count = 0. ##### Hints LEFT JOIN Departments to Students, then GROUP BY department ID or name.

Overview: This question evaluates proficiency with relational aggregation and join operations for counting related records across tables. It is commonly asked to assess understanding of SQL joins and grouping within the Data Manipulation (SQL/Python) domain and tests practical application of handling absent relationships rather than purely conceptual theory.

Given the Students and Departments tables, write a SQL query that lists each department name and the corresponding number of students in that department. Departments with no students must still appear in the result with a student_count of 0.

Tables

Students(id INTEGER, name VARCHAR, dept_id INTEGER)

Departments(id INTEGER, dept_name VARCHAR)

Hints

  1. Start from the Departments table and LEFT JOIN to Students on dept_id.
  2. Use COUNT(s.id) so that departments with no matching students return 0.

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