You are given three tables: 1. `company` - `employee_id` INT - `first_name` VARCHAR - `last_name` VARCHAR - `department` VARCHAR - `salary` DECIMAL 2. `employee_contact` - `employee_id` INT - `email` VARCHAR - `phone_number` VARCHAR - `years_at_company` INT 3. `employee_social` - `employee_id` INT - `linkedin` VARCHAR `employee_id` is the key used to join the tables. There are no date or timestamp columns in this problem, so no time-window or timezone assumptions are needed. Write SQL for the following progressive tasks: 1. Return every department that has more than one employee. - Required output: `department` 2. For each department, return the employee or employees with the highest salary. - If multiple employees tie for the highest salary in a department, return all of them. - Required output: `department, employee_id, first_name, last_name, salary` 3. From the highest-paid employee or employees in each department, return the contact details for those who have been at the company for more than 3 years. - Required output: `department, employee_id, first_name, last_name, salary, email, phone_number, years_at_company` Note: The `employee_social` table is provided as part of the schema, but it is not required for these three tasks.