Sort Every Concentric Matrix Border Clockwise

## Problem For each concentric border of a rectangular integer matrix, sort that border's values in ascending order and write them back clockwise starting at the border's top-left cell. Process every valid border through the center and return the transformed matrix. ### Function Contract Implement `sort_matrix_borders(matrix) -> list[list[int]]`. Do not mutate the input. ### Constraints - `1 <= rows, columns <= 200` and all rows have equal length. - Border `k` has top row `k`, bottom row `rows-1-k`, left column `k`, and right column `columns-1-k`. - Clockwise order is top left-to-right, right top-to-bottom, bottom right-to-left, then left bottom-to-top, without visiting a cell twice. - A one-row or one-column center is one border vector. ### Examples - `[[4,3],[2,1]]` returns `[[1,2],[4,3]]` because clockwise cells are top-left, top-right, bottom-right, bottom-left. - A one-row matrix is returned as that row sorted ascending. ```hint Enumerate coordinates first Generate each border's coordinate sequence once, collect and sort its values, then zip the sorted values back to those coordinates. ``` ### Edge Cases - Odd dimensions can leave one center cell. - A rectangular center may be a one-row or one-column vector. - Duplicates and negative values retain their multiplicities.