Local Search And Divide And Conquer
Asked of: Software Engineer
Last updated
What's being tested
Demonstrates the ability to find a local minimum using algorithmic tradeoffs between local search (greedy/hill-climbing) and divide-and-conquer (binary-search-like) approaches. Interviewers probe correctness proofs (termination, invariants), complexity reasoning, and handling edge cases like boundaries and equal neighbors.
Patterns & templates
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Binary search on 1D arrays — check
A[mid]vsA[mid-1]/A[mid+1], recurse left/right; guaranteesO(log n)comparisons when strict inequality holds. -
Mid-column divide-and-conquer for 2D — find global minimum in a column (
O(n)), compare to adjacent column, recurse to the half with smaller neighbor. -
Recurrence analysis — for an n×n matrix: ⇒ overall
O(n)time using mid-column strategy. -
Greedy local search (hill-climbing) — repeatedly move to a strictly smaller neighbor until none; simple,
O(n*m)worst-case on n×m grid. -
Boundary invariants — treat edges as having “missing” neighbors; endpoints can be local minima by definition.
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Plateau handling — break ties deterministically (e.g., prefer left/up), or treat
<=carefully to avoid infinite loops. -
Implementation tips — use
A[i][j]indexing checks, guard mid computation (mid = lo + (hi-lo)/2) to avoid overflow in large domains.
Common pitfalls
Pitfall: Assuming hill-climbing is always fast — adversarial inputs can force scanning most elements; argue worst-case complexity.
Pitfall: Using
<=vs<incorrectly on ties; this can cause nontermination on plateaus or miss valid local minima.
Pitfall: Off-by-one at boundaries — forgetting to check
A[0]/A[n-1](1D) or edge neighbors (2D) breaks correctness proofs.
Practice these
The practice cards below cover the canonical variants — solve all of them and time yourself.
Practice questions
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