03The 60-second brief

As a Software Engineer at Tata Consultancy Services (TCS), you are at the heart of building, modernizing, and maintaining large-scale digital technology solutions for Fortune 500 clients across banking, retail, healthcare, telecommunications, and manufacturing. TCS operates as one of the world's largest IT services and consulting organizations, meaning your software engineering contributions directly impact critical global infrastructure, enterprise applications, and cloud-native transformations.

TCS candidates report 4 rounds · ≈ 3-5 weeks. The stages below are what candidates describe, not a published process.

04What a Software Engineer does at TCS

Engineers at TCS work across various distinct tracks—including Ninja, Digital, and Prime hiring cadres—depending on technical complexity, algorithmic rigor, and domain expertise. Whether you are building backend microservices in Java and Spring Boot, designing interactive frontends with React or Angular, constructing data pipelines with Python and, or deploying cloud infrastructure on or, you are expected to deliver clean, maintainable code adhering to strict software engineering standards.

The role offers tremendous breadth and learning opportunities. You will collaborate daily with cross-functional teams, client technical leads, project managers, and quality assurance engineers to deliver end-to-end software solutions. Mastering core computer science concepts, object-oriented design, database optimization, and modern software development life cycle (SDLC) methodologies is fundamental to thriving in this position.

05The TCS interview process

TCS candidates report 4 rounds · ≈ 3-5 weeks. The stages below are what candidates describe, not a published process.

TCS National Qualifier Test

Because the format is not fixed, the first job in the room is classification. Listen to the opening question and decide what it is: a probe into work you have already described, a fresh problem to solve now, or a conversation about how you operate. Each wants a different register, and the common failure is forcing a rehearsed structure onto a question that did not ask for it. Running a full design ritual on a ten-minute debugging question reads as not listening. When you cannot tell which it is, ask how long they want to spend and answer at that depth.

What it evaluates

• Whether the shape of your answer matches the question, so a yes-or-no gets answered before it is justified and an open prompt gets a direction before a detour
• Whether you check how much depth is wanted instead of deciding for them, and whether you stop when the answer is complete rather than continuing until someone interrupts
• Whether you can be redirected in the middle of an answer without restarting it from the beginning
• Whether a question outside your experience gets an honest boundary followed by reasoning from what you do know, instead of a confident answer with nothing behind it

How to prepare

• Rehearse one project at three lengths, roughly thirty seconds, three minutes, and a full walkthrough at the depth of a design review, and practise switching between them when someone interrupts mid-telling
• Have someone ask you five questions of deliberately mixed type in one sitting without telling you the types, and score only whether you identified each one correctly before you started answering
• Draft the sentence you will use to check depth, along the lines of asking whether the short version is useful here or they want the detail, and use it in a real conversation this week so the day of the round is not its first outing

Technical Interview

Input bounds are the part of the prompt most often skimmed, and they usually contain the answer. They tell you which complexity class is admissible, which narrows the search before you have thought about the problem itself. As a rough planning figure, a compiled language does on the order of 10^8 simple operations per second and an interpreted one roughly an order of magnitude less. So n up to about twenty admits enumerating subsets, a few thousand admits a quadratic pass, and a million admits neither: you need near-linear, or linear with a log factor. If the bounds are missing, ask for them.

What it evaluates

• Whether the approach is justified by the stated input size rather than by whichever pattern you recognised first
• Whether you ask about the properties that change the algorithm: whether the input arrives sorted, whether duplicates occur, whether values are bounded integers, whether it all fits in memory
• Whether you can name the bottleneck in your own solution and what would remove it, even when you deliberately leave it in place
• Whether a claimed speedup is real, since memoising a recursion only helps when subproblems genuinely overlap and the state can be keyed cheaply

How to prepare

• For each algorithm you rely on, write down the largest n it handles in roughly a second, then check two of those figures by timing them in the language you will actually type in
• For two weeks, write one line naming your target complexity and the bound that justifies it before you write any code, then compare that line with what you ended up submitting
• Practise the conversion backwards: given a required O(n log n), list the mechanisms that get you there (sorting, a heap, an ordered map, divide and conquer) and choose by what the problem needs to query, not by what you used last

Managerial Interview

When a round has no standard shape, it is often there because something is still open: an area no earlier conversation reached, a round where the signal came out mixed, or a decision someone is not ready to make alone. Work out which by going back over what each earlier round actually covered rather than how it felt, and arrive able to give evidence on that point without being asked twice. Weak answers replay the loop's earlier material at the same depth. Strong ones go a level deeper and stay consistent with what you already said.

What it evaluates

• Whether your account of a project matches the one you gave earlier in the loop, since what you said before may be available to whoever runs this round
• Whether you can go a level deeper on something already covered, reaching the decision and its alternatives rather than repeating the summary
• Whether you state your own uncertainty accurately, including parts of a system you did not build and decisions you inherited, instead of claiming even ownership across all of it
• Whether you can answer a question you handled poorly earlier by naming what you missed, rather than delivering a polished second version as if the first had not happened

How to prepare

• Reconstruct the loop on one page: for each round, the questions you were asked and the answer you actually gave, not the better one you thought of afterwards. The gaps on that page are your best available guess at why this round exists.
• Take the two claims you made earlier that carry the most weight and assemble the backing for each: the measurement, the date, what broke, the decision you would make differently now.
• Write down the three facts about your work that must not drift between tellings, such as team size, timeline and your own role, and check your stories against that list rather than trusting recall under pressure

HR Interview

You cannot drill a format you do not know, so put the preparation into material that travels. Three pieces of your own work, each rehearsed until you can take a follow-up you did not anticipate, will carry a conversation or a code walkthrough equally well. Specificity is what separates that from filler. A number needs its definition before it means anything: a p99 is over some window and measured at some hop, and a server-side figure excludes the queueing and network time a client would see. The number you cannot qualify is the one to leave out.

What it evaluates

• Whether your examples carry detail only someone who did the work would hold, such as what the binding constraint actually was, which alternative you rejected and why it was worse, and what you measured on each side of the change
• Whether a number survives one follow-up, meaning you can say what it was measured over and whether it moved because of your change or merely alongside it
• Whether a failure is described with the specific change that followed it, rather than a lesson stated in general terms
• Whether your part in a team effort is stated accurately, including what other people did

How to prepare

• Write a page on each of three projects covering the constraint, the option you rejected, the measurement before and after, and what went wrong. Cut any line you cannot take a follow-up on, since you are writing the parts you will be pressed on rather than a summary.
• Recover the real figures while you still have access: request volume, data size, latency with its percentile and window, team size, timeline. Note where each came from, whether a dashboard, a design document or memory, and mark the estimates so you can say which they are out loud.
• Take your weakest project story to someone who works in a different area and have them ask why four times in succession. The point where you run out of answer is the part to go and re-read before the round.

06Questions TCS candidates report

These are the prompts PracHub has collected for this role and company. They are a record of what candidates describe being asked, so treat them as the shape of the conversation rather than a script TCS works from.

Data structures and algorithms

Every fast solution here throws work away, and the claim you have to defend is that the discarded work could not have held the answer. A two-pointer walk over sorted values advances the left index only because every remaining pair using that element is also too small. A monotonic deque drops an element because a larger one sits to its right and will stay in the window longer. Say that sentence out loud. A weak answer names the technique and shows it passing the given examples, which is indistinguishable from a wrong technique that happens to pass the given examples.

• How do you implement an AVL Tree or perform rotations (LL, RR, LR, RL) to maintain balance?
• Implement a circular queue or deletion operation in a binary search tree from scratch.
• Write a program to print logic-based star patterns, such as an equilateral triangle or a V-shaped pattern.
• Write a function to reverse an array or string in-place without using language-native utility methods.

System design and architecture

The design is the data model and the interface; the boxes follow from them. Write the entities, the key each row is stored under, and then, for every read the product needs, the path from a key to the rows returned. Do the same for each write, including whatever else must change in the same operation. Most designs fail here rather than at scale, when a read the feature depends on turns out to need a scan or a fan-out across every partition. The strongest answers state the queries first and let the storage choice fall out of them.

• How do microservices communicate with each other using Spring Boot, REST APIs, and message brokers?
• How do you manage infrastructure as code using Terraform and secure sensitive state secrets during CI/CD deployments?

Behavioural and engineering judgement

A reversal is the easiest of these to tell badly, because the honest version sounds like a mistake and the flattering version sounds like nothing happened. Give the trigger: the specific observation that made continuing worse than stopping, dated to when it arrived rather than when it became undeniable. Then give what stopping cost, whether that was work discarded, a migration left half-finished, or a team told the dependency they had built against was moving. The answer that stands out names a stopping condition set before it was needed, or says plainly that none had been set.

• Tell me about a challenging technical roadblock you encountered in a recent project and how you resolved it.
• How do you handle project conflicts or tight deadlines when working in cross-functional team environments?

Other topics

A large share of these are really questions about evidence: why something is slow, or how much of something you would need. Convert the prompt into a number or an observation. For diagnosis, name the measurement that would tell two candidate explanations apart and say what each predicts before you collect it. For sizing, carry the units through and stop at one significant figure. Listing everything that could plausibly be true is what the weak version looks like. What separates the strong one is a hypothesis, the observation that would falsify it, and what the arithmetic already rules out before any new data arrives.

• Explain the concepts of abstraction and encapsulation with real-world software examples.

07Practice exercises with worked solutions

The prompts above tell you what gets asked. These are PracHub exercises written to drill the same skills, with the reasoning spelled out so you can check your own answer instead of guessing whether it was good enough.

Rebuild an hourly rollup with deduplication and late-arrival accounting

From usage_event (event_id, tenant_id, workspace_id, environment, sku, quantity numeric(20,6), idempotency_key, occurred_at, ingested_at), produce the values usage_rollup_hourly should hold for one tenant over one day: per (workspace_id, sku, hour_start) the deduplicated quantity_sum, event_count and source_max_ingested_at, bucketed by occurred_at. Duplicates share (tenant_id, idempotency_key). Also report, per hour, the running total across the day and the share of quantity that arrived more than two hours after the hour began. Write the query, and state which duplicates a daily unique index cannot catch.

How a strong candidate works it

• Deduplicate in its own CTE before any aggregation, because a SUM cannot be un-summed: row_number() over (partition by tenant_id, idempotency_key order by ingested_at, event_id) = 1. Include the tiebreaker. Without it the surviving row is non-deterministic when two duplicates share an ingested_at, and a rollup described as deterministically recomputable then disagrees with itself between runs.
• Bucket on occurred_at and nothing else, and pin the timezone explicitly. date_trunc('hour', timestamptz) truncates in the session's TimeZone setting, so the same query run by a session set to a non-UTC zone buckets differently; use the three-argument date_trunc('hour', occurred_at, 'UTC') on PostgreSQL 16 or later, or date_trunc('hour', occurred_at at time zone 'UTC') at time zone 'UTC' before that. Filter environment = 'production' explicitly, since metering covers three environments and billing covers one.
• Aggregate to the grain with sum(quantity), count(*) and max(ingested_at). The last is not decoration: it is the watermark the row consumed up to, and without it there is no way to prove afterwards what a number did and did not include.
• Compute the late share inside the dedup-and-aggregate step as a conditional aggregate, sum(quantity) filter (where ingested_at > hour_start + interval '2 hours'), then divide by the hour's total. Compute the running total as a window over the already aggregated rows: sum(quantity_sum) over (partition by workspace_id, sku order by hour_start rows between unbounded preceding and current row). Running either over raw rows puts the duplicates back.
• Answer the index question exactly. The unique constraint is on (ingested_day, tenant_id, idempotency_key), because a unique index on a partitioned table must contain the partition key. It therefore deduplicates only within one ingest day and admits a duplicate whose retry crosses midnight or whose replay runs a week later. That is why this CTE dedups across the whole window being recomputed, and why the dedup horizon is a correctness parameter rather than a retention cost.
• Keep the numeric type all the way through. quantity is numeric so the sums are exact; a cast to double precision anywhere in this pipeline reintroduces drift that surfaces only as a few unreconcilable cents per tenant per month, long after the query is out of anyone's mind.

Expected result (40 min): One query: a dedup CTE using row_number() over (partition by tenant_id, idempotency_key order by ingested_at, event_id); aggregation by (workspace_id, sku, hour_start) producing quantity_sum, event_count and max(ingested_at) plus a filtered late-quantity aggregate; a running total as a window over the aggregated rows; and an explicit statement that the partition-scoped daily unique index cannot catch a duplicate that crosses the ingest-day boundary or arrives in a later replay.

Check yourself

• Row count after dedup equals raw count minus injected duplicates, exactly.
• The running total at the final hour equals the ungrouped day total for that (workspace, sku).
• Two consecutive runs over static data return byte-identical rows.
• Every hour_start is hour-aligned in UTC and unchanged by the session's TimeZone setting.

Follow-ups

• A dispute forces the same recompute over 40 days for one tenant. What changes about the dedup CTE's memory use and the chosen plan, and what would you do about it?
• Two runs a minute apart return different quantity_sum values for an hour that is already closed. Give two mechanisms that produce that, and the single query that distinguishes them.
• Express the same rollup incrementally so it does not re-scan the day each time the watermark advances. What does the incremental version stop being able to answer?

Decide which facts an invoice line copies instead of joining

invoice_line_item already denormalises tenant_id, which is reachable through invoice_id, and stores amount_minor even though quantity times unit_price_micros would recompute it. A reviewer asks you to normalise both away, and separately asks whether the tenant's legal name and billing address should be copied onto the invoice header. Decide each case. For every field you keep denormalised, name the read pattern or the invariant that justifies it, the anomaly the copy can develop, and the mechanism that prevents that anomaly here.

How a strong candidate works it

• Split the question into two kinds of copy, because they fail differently. A copy of a currently mutable fact is a cache: it drifts and needs invalidation. A copy of a fact frozen at write time is not a cache at all, it is the record of what happened, and normalising it away destroys information the source no longer holds.
• Keep tenant_id on the line. It costs 8 bytes, it leads every index on the table so no read is ever accidentally cross-tenant, and it turns a wrong join into an empty result rather than another tenant's money. Prevent the drift structurally: a unique constraint on invoice (invoice_id, tenant_id) plus a composite foreign key from the line on (invoice_id, tenant_id) makes a mismatched pair impossible, so the database enforces agreement instead of a code review.
• Keep amount_minor. Rounding must happen exactly once, at a named site, with a stated mode (half-even here). If readers recompute from quantity and unit_price_micros, every reader owns a rounding decision, and half-up and half-even diverge systematically across thousands of lines rather than cancelling out. A check constraint can bound the stored value but deliberately cannot re-derive it.
• Copy the legal name and billing address onto the invoice header, written once and never updated. The statement must show what was true when it was sealed, and the tenant record will change afterwards. This is a snapshot for the same reason source_rollup_watermark is stored per line: without it, nobody can reconstruct what the customer was told.
• Name the read pattern that pays for all of it. Rendering, dispute response and export are per-tenant, per-period reads over thousands of lines that would otherwise join back to slowly changing dimensions that no longer hold the historical value. The write side is a once-per-period batch, so the extra columns cost nothing that matters.
• Concede the case where the reviewer is right: a mutable operational attribute such as the tenant's current plan name has no business on a line. If a report wants it, join. If a statement needs the plan as of the period, that is another snapshot and it belongs on the header with the rest.

Follow-ups

• Write the composite foreign key and the unique constraint it requires on the parent. What does it cost on every line insert, and what does it do to a bulk load?
• A tenant is renamed after being invoiced. Which rows change, and what does the customer see on last quarter's PDF?
• Where does currency live, and what breaks if a tenant's billing currency changes between two periods?

Hold a tenant to a trailing sixty-second request limit

The gateway must hold each tenant to R requests in any trailing 60 seconds, in aggregate across three regions and every pod, within a budget of under 10 ms added p99. Peak is 30,000 requests/second across 200,000 active tenants, and traffic is heavily skewed toward a handful of them. Give an exact single-process algorithm with its amortised per-request cost and its memory per tenant, then a bounded-memory approximation and the worst-case overshoot it actually admits. Say what the distributed version does when the counter store is unreachable.

How a strong candidate works it

• Exact, single process: a per-tenant deque of request timestamps. On arrival, pop from the front while front <= now - 60s, then admit if the remaining length is below R and push. Each timestamp is pushed once and popped once, so the cost is O(1) amortised. The O(R) version is the one that re-filters the whole deque on every request.
• Quote the memory. R = 1,000 across 200,000 active tenants is up to 2 x 10^8 timestamps at 8 bytes, about 1.6 GB, and that is the worst case rather than the mean, because the long tail of small tenants holds almost nothing. Skew helps you here and hurts you in the sharding decision.
• Bounded alternative, with its real bound stated: a fixed 60-second counter is O(1) memory but admits close to 2R across a 60-second span straddling a boundary. The weighted two-bucket estimate, prev * (60 - elapsed)/60 + cur, is better on smooth traffic but assumes the previous window's arrivals were uniform; an adversary packing them at the end of that window is undercounted and can still approach 2R. Say that rather than calling it exact.
• Token bucket is the usual gateway answer and a different contract: O(1) state per tenant (tokens, last_refill), a sustained rate, and a deliberate burst allowance equal to the bucket size. Choose it when a burst is acceptable and the log when the limit is contractual.
• Distributed: the limit is per tenant in aggregate, so a local bucket of R/N per pod is wrong in both directions under skew. A tenant landing on one pod is throttled at R/N, and a tenant spread evenly across pods exceeds R. The shared check must be a single atomic round trip, one script or one increment-and-compare, never read-then-write, and it must fit inside the 10 ms p99 budget.
• Decide the unavailable case in advance and write it down. Failing open keeps the product up and lets a tenant exceed its limit for the duration; failing closed converts a counter-store outage into a full outage. Most gateways fail open on rate limits and closed on authorisation, and those are two separate decisions made separately.

Expected result (25 min): The exact deque never admits more than R in any trailing 60-second window. The fixed counter admits close to 2R across the boundary. The weighted estimate lands between the two on this burst and approaches 2R once the previous window's requests are packed at its end.

Check yourself

• Total pops equal total pushes, which is what makes the amortised O(1) claim true rather than merely asserted.
• Sliding the whole burst by 30 seconds changes the fixed counter's result and leaves the deque's unchanged.
• Running two processes each limiting to R/2, against a tenant that sends everything to one of them, shows that tenant throttled at half its contractual limit.

Follow-ups

• One tenant sends 40% of all traffic. What does that do to a single counter key, and what do you shard on instead?
• Quotas rather than rate limits: the check is select used; if used < limit then insert. Name the isolation level that still permits the overshoot, and the two fixes.
• How do you return an accurate Retry-After from the exact algorithm without a second scan?

Specify webhook signature verification a customer can implement

The webhook-delivery service signs each payload before POSTing it to a customer endpoint. Write the signature specification a customer implements in their own language: the header format, exactly which bytes are signed, the algorithm, how replay is bounded, and how a signing secret rotates without a delivery gap. Then write the verification steps the customer performs, in order, including what they compare and what they return on failure. Constraint: most customers reach for their web framework's parsed JSON body by default. Deliverable: the spec section plus reference pseudocode.

How a strong candidate works it

• Sign the concatenation of the timestamp and the raw body, t + "." + body, and emit a header of the form t=<unix seconds>,v1=<hex>. The timestamp has to be inside the MAC, or an attacker re-stamps a captured body and the tolerance window buys nothing.
• Require the raw request bytes. A framework that parses JSON and re-serialises it changes key order, whitespace and number formatting, so the spec must tell the customer to capture the body before the parser runs and give the middleware note for each common framework.
• Use HMAC-SHA256, not sha256(secret || body): SHA-256 is a Merkle-Damgard construction, so the naive form admits length extension. Require a constant-time comparison as well, since a short-circuiting byte compare leaks the expected prefix under repeated probing.
• Bound replay in two layers: reject when |now - t| exceeds a stated tolerance such as 300 seconds, then deduplicate on the event identifier header. The tolerance is what makes the customer's dedup store finite rather than unbounded.
• Rotate by allowing two live secrets and emitting both signatures in one header (v1=<old>,v1=<new>); the customer accepts if any candidate matches, so neither side needs an instantaneous cutover. A failed verification returns 400 and the body is not processed.

Expected result (15 min): A spec where the signed input is the timestamp joined to the exact raw bytes, the algorithm is HMAC-SHA256 compared in constant time, replay is bounded by a stated tolerance plus event-id deduplication, and rotation is an overlap of two accepted signatures rather than a cutover.

Check yourself

• The timestamp is inside the signed string, not merely sent alongside it.
• The spec names raw bytes and says where the customer gets them before parsing.
• Rotation requires no coordinated instant on either side.
• The reason for HMAC over sha256(secret || body) is stated as length extension, not as a preference.

Follow-ups

• A customer's verification passes locally and fails in production behind a proxy that re-encodes the response body. Where do you look first?
• Why sign with a per-endpoint secret rather than the tenant's API key?

Regional error rate explodes after a dependency merely slows

A control-plane read replica in one region degrades from 4 ms to 120 ms. Within ninety seconds that region's gateway error rate rises from 0.01% to 40% and its p99 becomes bimodal, one mode near the old p99 and one at the client timeout. The other two regions are unaffected. The gateway retries control-plane reads three times with exponential backoff and no jitter. Give an ordered checklist that separates trigger from amplifier, the offered-load arithmetic, and the controls that break the loop.

How a strong candidate works it

• Split the incident into three questions before touching a control: what started it, what amplified it, and what would make recovery slow. Here they are the replica slowdown, the retry policy interacting with queueing, and a synchronised unjittered herd at recovery. They are different mechanisms and each needs its own control.
• Read the distribution rather than the mean. A bimodal p99 with one mode pinned at the client timeout is two populations, not one degraded path; split latency by cache hit and miss and confirm the fast mode is hits and the timeout mode is misses that reached the replica.
• Do the load arithmetic. Three retries turn one client request into up to four upstream requests, so offered load reaches roughly 4x on a dependency that is already slower, and it arrives at the worst moment. With utilisation approaching one, queueing delay grows superlinearly, which is why a 30x latency increase upstream does not produce a 30x increase downstream, it produces timeouts.
• Break the loop with controls that bound offered load rather than with more attempts: a concurrency limit on the control-plane client so at most N calls are in flight and the remainder fail fast, a circuit breaker scoped per dependency and region, and a retry budget capping retries at a small fraction of base traffic so amplification has a ceiling that does not depend on how many clients are retrying.
• Add full jitter to whatever retries survive, sleeping uniformly in [0, min(cap, base x 2^attempt)], so attempts de-correlate instead of arriving in waves aligned to the moment of failure.
• Decide the unreachable-dependency behaviour in advance, because it is the actual product decision underneath: serving from an expired credential cache keeps the product available while extending a revoked key's life past the stated bound, and failing closed converts a dependency degradation into a total outage. State the mode and the staleness number rather than letting the timeout choose.

Follow-ups

• The replica recovers. Describe what happens in the first ten seconds with your controls in place versus without them.
• Which single metric would have paged before the error rate moved, and why is upstream latency by itself not it?
• Requests that fail fast under the concurrency limit still need an answer. What does the gateway return, and what does it do to the usage event it would otherwise have emitted?

Argue against failing open when the control plane is unreachable

The gateway caches credential-to-context decisions with a sixty-second TTL. A design proposal says that when control-plane reads fail, pods should keep serving from expired entries indefinitely so a control-plane outage never becomes a product outage. You believe that converts every revocation into an unbounded one. Describe a design you argued against while it was still a live proposal: what you measured or modelled to make the case, what you conceded, who decided, and what happened afterwards. Say what would have changed your mind before the decision, not after it.

How a strong candidate works it

• Reframe it from a values argument into a bounded-staleness argument. Both sides already accept the cache; the disagreement is only about the ceiling on how long a revoked credential keeps authorising. Put a number on the table — serve stale for up to fifteen minutes, then fail closed — and make the other side argue against a number rather than against a principle.
• Bring arithmetic rather than adjectives: the rate of revocations with revoked_reason in ('suspected_leak','auth_version_bump'), the observed distribution of control-plane unavailability, and the product of the two, which is expected requests served by revoked credentials per outage-hour. At 30k requests/second the unbounded version is not a subtle exposure and the number says so.
• Concede the strong half of the opposing case first, because that is what buys you the room: failing closed turns one service's outage into a total outage across three regions, and a control plane doing tens of writes per second is not engineered to the gateway's availability target. A proposal you have not steelmanned reads as reflex.
• Propose the asymmetry that usually resolves this: stale entitlements cost bounded money (a quota fifteen minutes out of date over-serves by a computable amount), while a stale revocation costs unbounded access. Split the cached decision by what it authorises, give the two halves different staleness ceilings, and let the entitlement half fail open while the revocation half fails closed.
• State the propagation dependency plainly, since it is the part that is missed: validity is also derived from the principal's auth_version, so password reset and sign-out-everywhere flow through this same cache. A design that bounds staleness for explicit revocation and not for auth_version bumps has only fixed half of it.
• Say who decided, and what you did afterwards in either outcome: write the decision down with its number and a review date, and instrument the exposure you were worried about so the next round of the argument is settled by data instead of by seniority.

Follow-ups

• Publish-subscribe invalidation is lossy under a partition, and a TTL is the only hard bound. What TTL do you pick, and what does it cost you at 30k requests/second?
• The key was revoked because it was found in a public repository. Does your answer change, and where does that urgency live in the design?
• You lost the argument and six weeks later the failure you predicted happens. What do you say in the review, and what do you not say?

08Where candidates lose points

Paginating a growing table with limit and offset

Two unrelated defects share the idiom. Correctness: rows inserted or deleted between page requests shift the window, so a consumer walking an export skips rows and sees others twice, which for a customer-facing sync is silent data loss rather than an error anyone notices. Cost: the database still produces and discards the skipped rows, so page N costs time proportional to N times the page size and a deep page on a large table degrades from milliseconds to seconds. Keyset pagination over a stable, unique, indexed ordering -- where (created_at, id) < ($1, $2) order by created_at desc, id desc limit $3 -- is constant-cost per page and immune to shifting, on the precondition that the cursor columns never change value for a row, which disqualifies updated_at as a cursor.

Holding money in a floating-point type, or rounding it more than once

Binary floating point cannot represent 0.01 or 0.1 exactly, so sums drift and two code paths that should agree disagree by cents nobody can trace back. The fix is integer minor units or an exact decimal type end to end, with sub-cent rates expressed as scaled integers such as micro-units, because a per-request price genuinely is smaller than a cent. The second half of the trap is rounding position: rounding each line and then summing gives a different total from summing and rounding once, and half-up and half-even diverge systematically across many lines, so rounding must happen at one named place and every downstream reader must carry the rounded value rather than recompute it from quantity and rate.

Reading the constraints as preamble rather than as part of the problem

The bounds are usually there to eliminate the obvious approach: n up to 10^5 makes an O(n^2) scan roughly 10^10 operations, far outside any per-test time budget, and an input larger than memory rules out loading it at all. When a bound is not given, ask for it, then say out loud which approach it kills.

Naming no test cases at all

State what you would test before being asked: empty input, a single element, all elements equal, the maximum permitted size, and the input that exercises the branch you just wrote. It costs thirty seconds and is much of what separates someone who has shipped code from someone who has only solved puzzles.

09Breadth then depth, for a generalist facing a mixed loop

Four days sample coding, design, fundamentals and the practical rounds at deliberately shallow depth, which is enough to surface the topics you did not know were in scope. That map, rather than a guess made on day one, decides where the last three days go.

Day 1 — Coding, one pass at shallow depth

• Solve one problem from each of six families, an array with two pointers, hash counting, binary search, a tree traversal, a graph traversal and one dynamic program, under a hard twenty-minute cap with no extensions, marking each finished, late, or stalled.
• For every stall, write the exact move you could not make rather than the subject, so the note reads could not turn the recurrence into a loop rather than bad at dynamic programming.
• Fix nothing today. The value of the pass is the unfixed record.

Deliverable: Six timed attempts marked finished, late or stalled, each stall carrying a named blocking move.

Day 2 — Design, one pass at shallow depth

• Spend twenty minutes each on three different shapes, a read-heavy feed, a write-heavy ingest path, and something needing a transaction across two entities, stopping each at requirements, interface and data model.
• After each, write the first question you could not answer, which is usually a number you could not estimate or a failure mode you had no vocabulary for.
• Mark which of the three you would be most relieved not to be asked, and treat that as data rather than as a preference.

Deliverable: Three shallow designs, each with the first unanswerable question written at the bottom.

Day 3 — Fundamentals and the practical rounds

• Answer eight short questions in writing at four minutes each, covering the material that fills the gaps between the big rounds: what happens between a URL and a rendered page, what an index costs on write, when a process is preferable to a thread, and what conditions a deadlock requires.
• Do one thirty-minute practical task of the kind a take-home compresses: read an unfamiliar two-hundred-line file and write what it does, what you would change, and the one thing you remain unsure of.
• Score every answer fluent, correct but slow, or absent, and keep the absent ones visible.

Deliverable: Eight scored short answers and one written reading of unfamiliar code.

Day 4 — The rounds that are about you, and the map

• Deliver three behavioural answers aloud against a timer, a conflict, a failure you owned, and a decision made without enough information, marking any that ran past three minutes or contained no number.
• Assemble the map: every marked item from days one to three on a single page, sorted by how likely it is to appear in your loop rather than by how uncomfortable it felt.
• Choose exactly two areas for the remaining three days and write down what you are deliberately abandoning.

Deliverable: A one-page scored map of the whole surface area with two areas chosen and the rest explicitly abandoned.

Day 5 — First chosen area, to the depth you skipped

• Work the higher-ranked area in four focused blocks, choosing items one level above where you stalled rather than repeating what already works.
• After each block write the rule you extracted in one sentence with its precondition attached, since a rule carrying no precondition is exactly what fails under a variation.
• Re-attempt the day-one or day-two item that exposed this area and compare against the original timing.

Deliverable: Four worked blocks, a timed re-attempt against the original, and three one-sentence rules with preconditions.

Day 6 — Second chosen area, where the gap is coverage rather than speed

• Treat the second area differently from the first. Day five drilled something you could already half-do; this one is usually a topic you had simply never met, so build one worked reference example end to end and keep it, rather than attempting six problems badly.
• Write down the vocabulary you were missing on day two or three, five terms at most, each with the one sentence that makes it usable in an answer rather than the textbook definition.
• Redo the shallow attempt that exposed this area and note whether you now fail later in the problem, because moving the failure point is the realistic gain from a single day and is worth more than a score that did not change.

Deliverable: One worked reference example for the newly covered area, a five-term vocabulary list, and a note on where the failure point moved.

Day 7 — Reassemble the loop

• Sit two rounds back to back with no gap, ordering them so the area you chose second comes last, because the map was built from rested, isolated attempts and the loop will reach your weaker area when you are already spent.
• Write where the second round suffered from the first, which is normally the point at which structure collapses into narration.
• Reduce the week to one page holding only the rules you can state without reading them.

Deliverable: Mock notes on cross-round carryover plus a one-page card of rules you can recite from memory.

10Frequently asked questions

Is this an official TCS interview guide?

No. It is PracHub's own research and practice material for the Software Engineer role at TCS. Rounds and questions reflect what candidates have reported, not a process TCS has published, and they change over time. Confirm the current format and scope with your recruiter.

How difficult is the TCS Software Engineer interview process?

The difficulty depends heavily on the targeted hiring band. The Ninja track focuses primarily on foundational aptitude, basic coding, OOPs, and standard SQL queries, whereas the Digital and Prime tracks require advanced algorithmic implementation (e.g., trees, dynamic programming) and deep framework knowledge.

How long does the complete recruitment process take from exam to offer?

The timeline ranges between 2 to 6 weeks, depending on whether you participate in a centralized campus drive or an off-campus walk-in event. High-volume drive results may occasionally take longer due to background verification and document checks.

Can non-Computer Science engineering graduates apply for this role?

Yes, graduates from non-CS branches (such as ECE, EEE, Mechanical, or Civil) can apply provided they satisfy academic percentage thresholds and demonstrate proficiency in programming fundamentals, OOPs, and SQL during interviews.

What differentiates candidates who receive Prime or Digital offers over Ninja offers?

Candidates awarded Digital or Prime offers exhibit exceptional performance in the NQT coding section, implement complex data structures from scratch during live interviews, show familiarity with modern web/cloud stacks, and clearly articulate system design and project architecture.

11Keep practising

• Software Engineer question bank — cross-company practice.
• Interview preparation framework
• All interview guides