Check palindrome number and next palindrome

## Problem You are given a **non-negative integer** `n`. 1. Determine whether `n` is a palindrome in base-10 (it reads the same forward and backward). 2. **Follow-up:** Return the **smallest palindrome integer strictly greater than `n`**. ### Examples - `n = 1221` → palindrome: `true` - `n = 999` → palindrome: `true` - `n = 132` → next palindrome: `141` - `n = 9` → next palindrome: `11` - `n = 10` → next palindrome: `11` ### Input / Output - Input: integer `n` - Output: - Part (1): boolean - Part (2): integer ### Constraints (assume) - `0 ≤ n ≤ 10^18` (so solutions should not rely on converting to a fixed-size 32-bit int) - The follow-up should be efficient for large `n` (avoid incrementing one-by-one).