Compute total after discounting most expensive item

## Problem You are given: - An array `prices` of length `n`, where `prices[i]` is the price of the *i-th* item. - An integer `discountPercent` (0 to 100). A promotion applies **only to one item**: the **most expensive** item receives `discountPercent` percent off. If there are multiple items tied for the maximum price, discount any one of them (the result is the same). The discounted amount may be fractional. The final amount to pay is: \[ \left\lfloor \sum prices - (\max(prices) \cdot discountPercent/100) \right\rfloor \] Return the final amount to pay as an integer. ### Input - `prices`: array of non-negative numbers (integers or decimals) - `discountPercent`: integer in `[0, 100]` ### Output - Integer: the floored total amount to pay. ### Constraints (typical) - `1 <= n <= 2 * 10^5` - `0 <= prices[i] <= 10^9` ### Example - `prices = [100, 50, 25]`, `discountPercent = 20` - max price = 100, discount = 20 - total = floor(175 - 20) = `155`