Determine Whether the Last Array Index Is Reachable by Forward Jumps

You are given a list of non-negative integers `nums` and start at index `0`. The value `nums[i]` is the longest jump you may make from index `i`: from `i` you may move forward to any index `j` with `i < j <= i + nums[i]`, as long as `j` is a valid index. Return `True` if some sequence of jumps reaches the last index, `len(nums) - 1`, and `False` otherwise. ### Function Signature ```python def can_reach_last_index(nums: list[int]) -> bool: ``` ### Rules - Jumps only move forward, and from index `i` you may choose any jump length from `1` up to `nums[i]`. A jump may not land beyond the last index, but any shorter jump is still allowed. - A value of `0` means no jump can be made from that index. - If `nums` has a single element, you are already at the last index, so the answer is `True`. ### Constraints - `1 <= len(nums) <= 10^5` - `0 <= nums[i] <= 10^5` ### Examples **Example 1** - Input: `nums = [1, 2, 0, 3, 0]` - Output: `True` - Explanation: Jump from index `0` to index `1`, then a jump of length 2 from index `1` to index `3`, then from index `3` to the last index, `4`. **Example 2** - Input: `nums = [3, 1, 1, 0, 2]` - Output: `False` - Explanation: Indices `1`, `2` and `3` are reachable, but every route ends at index `3`, whose value is `0`. Index `4` is never reached. **Example 3** - Input: `nums = [0]` - Output: `True` - Explanation: The start is already the last index.