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This question evaluates understanding of string data structures, memory layout, copy complexity, move semantics, and language-specific behavior such as Rust's move model.

  • Medium
  • Character.AI
  • Coding & Algorithms
  • Software Engineer

Explain strings and copy complexity

Company: Character.AI

Role: Software Engineer

Category: Coding & Algorithms

Difficulty: Medium

Interview Round: Technical Screen

##### Question What is a string? What fields does a struct string contain, and how would you implement it yourself? What is the time complexity of copying a string? How can move operations be made more efficient? In Rust, is move just modifying a reference?

Quick Answer: This question evaluates understanding of string data structures, memory layout, copy complexity, move semantics, and language-specific behavior such as Rust's move model.

You are given a sequence of commands that operate on named string variables using a toy string library. Each variable may refer to a heap-allocated buffer that stores its content. You must simulate three kinds of data ownership operations—deep copy (copy), move (move), and copy-on-write clone (cowcopy)—plus creation (new) and append (append). Track and return outputs for query commands. Cost is defined as the total number of bytes physically copied due to allocations or mutations. Rules: 1) new v s: allocate a new buffer with contents s and bind it to v; cost increases by len(s). 2) copy a b: deep copy contents of a into a new buffer and bind to b; cost increases by len(a). If a is unbound, b becomes unbound and no cost. 3) cowcopy a b: bind b to the same buffer as a (increase reference count); no immediate cost. If a is unbound, b becomes unbound. 4) move a b: transfer binding from a to b in O(1); a becomes unbound; no cost. If a is unbound, b becomes unbound. 5) append v t: append string t to v. If v is unbound, treat as new v t. If v's buffer has refcount > 1, detach (copy-on-write): allocate new buffer with old contents plus t; cost increases by old_len + len(t). If refcount == 1, grow in place; cost increases by len(t). 6) len v: output the current length of v (0 if unbound). 7) cost: output the cumulative cost so far. Rebinding a variable first releases its previous buffer reference; buffers are freed when their reference count reaches 0. Return a list of integers corresponding to outputs of len and cost commands in order.

Constraints

  • 1 <= len(ops) <= 100000
  • Each command is one of: new v s | copy a b | cowcopy a b | move a b | append v t | len v | cost
  • Variable names v, a, b: [A-Za-z0-9_]{1,20}
  • Strings s, t: lowercase ASCII letters only, 1 <= len(s), len(t) <= 100000
  • Sum of lengths of all provided s and t over ops <= 1000000
  • All operations must be processed in order; outputs are only for len and cost commands
  • Cumulative cost fits in 64-bit signed integer

Hints

  1. Track buffers by IDs with fields: length and reference count.
  2. Map variable names to buffer IDs. Rebinding should decrement the old buffer's refcount and free it if it becomes zero.
  3. Deep copy allocates a new buffer; cowcopy just shares the buffer (increment refcount).
  4. On append, if refcount > 1, detach (copy old content) before mutating.
Last updated: Mar 29, 2026

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