As a Software Engineer at Pan American Silver, you are tasked with bridging the gap between cutting-edge technology and the complex, high-stakes world of precious metals mining. Your work affects the efficiency, safety, and operational intelligence of Pan American Silver's global mining assets. By developing software solutions, you enable the company's teams to manage data, optimize infrastructure, and maintain the company's performance standards.
This role is both critical and intellectually demanding. You will navigate the intersection of IT infrastructure and industrial operations, requiring you to understand not just code, but the specific business requirements of the mining sector. Whether you are improving existing systems or architecting new tools, your contributions serve as the backbone for operational excellence. Joining Pan American Silver means you will play a vital role in a sector where technology is increasingly the key to sustainable and efficient production.
Preparation focus
editorialNo round sequence has been reported for this company, so work the categories below and confirm the format with your recruiter.
What to demonstrate
- Breadth across SQL, experimentation and product reasoning
- Ability to state assumptions before choosing a method
How to prepare
- Drill the practice exercises below and time yourself
- Prepare three quantified stories about decisions you drove
PracHub editorial advice for the preparation topics above.
Paginating a growing table with limit and offset
Two unrelated defects share the idiom. Correctness: rows inserted or deleted between page requests shift the window, so a consumer walking an export skips rows and sees others twice, which for a customer-facing sync is silent data loss rather than an error anyone notices. Cost: the database still produces and discards the skipped rows, so page N costs time proportional to N times the page size and a deep page on a large table degrades from milliseconds to seconds. Keyset pagination over a stable, unique, indexed ordering -- where (created_at, id) < ($1, $2) order by created_at desc, id desc limit $3 -- is constant-cost per page and immune to shifting, on the precondition that the cursor columns never change value for a row, which disqualifies updated_at as a cursor.
Holding money in a floating-point type, or rounding it more than once
Binary floating point cannot represent 0.01 or 0.1 exactly, so sums drift and two code paths that should agree disagree by cents nobody can trace back. The fix is integer minor units or an exact decimal type end to end, with sub-cent rates expressed as scaled integers such as micro-units, because a per-request price genuinely is smaller than a cent. The second half of the trap is rounding position: rounding each line and then summing gives a different total from summing and rounding once, and half-up and half-even diverge systematically across many lines, so rounding must happen at one named place and every downstream reader must carry the rounded value rather than recompute it from quantity and rate.
Writing code before the input contract is pinned down
Before the first line, state the types, the size bounds, whether duplicates, negatives or an empty input are possible, whether the input is sorted, whether you may mutate it, and what the function returns when nothing matches. Every one of those answers changes the code, and discovering one at minute twenty costs a rewrite you no longer have time for.
A cache with no invalidation story
Say how an entry goes stale, how long you can serve it stale, and what happens when many requests miss the same key at the same instant. One popular key expiring under load sends every concurrent request to the origin together; single-flight coalescing, jittered expiry, or serving stale while revalidating are the standard answers.
Choose a category, try a prompt, then open its approach, worked solution or follow-up when you need it.
Schedule ordered webhook retries with a heap of subscription queues
Design the in-memory scheduler for webhook delivery. Up to 20 million rows sit in status pending or failed_retryable across 200,000 subscriptions, each row carrying next_attempt_at and attempt_count, and each endpoint having a circuit breaker. Deliveries for one subscription must be attempted in order, so at most one attempt per subscription may be in flight. Support due(now), complete(delivery, outcome) and insert(delivery) in O(log S), where S is the subscription count rather than the delivery count. Give the backoff formula you schedule retries with.
Approach
- Key the global heap by subscription, not by delivery. Each subscription owns a FIFO of its due deliveries in event order; the heap holds one entry per eligible subscription, keyed by its head's
next_attempt_at. That is 200,000 heap entries instead of 20 million, and it makes the one-in-flight rule structural rather than a check somebody can forget. due(now): peek the minimum. If its key is in the future, sleep until then instead of spinning. Otherwise pop it, move the subscription into an in-flight set, and do not re-push it. A subscription absent from the heap cannot be dispatched twice, which is precisely how ordering is preserved.complete: on success, drop the head and re-push the subscription keyed by its new head, or leave it out when the queue empties. On a retryable failure, incrementattempt_countand setnext_attempt_at = now + uniform(0, min(cap, base * 2^attempt)), sampled uniformly across the whole interval. That is full jitter; deterministic backoff re-synchronises the herd you just created.- Circuit breaker: park the subscription in a second heap keyed by its half-open time, so an endpoint dead for six hours costs one heap entry and zero attempts rather than consuming worker slots. Admit exactly one probe at half-open and close the breaker only on its success.
- Say the price of the ordering guarantee out loud. One in-flight attempt per subscription means an endpoint answering in 10 seconds drains at 0.1 deliveries/second however many workers you run, and its backlog grows until it recovers. If the customer does not need order, allow k in flight and document delivery as unordered; that is the trade, and it is a product decision.
- All three operations are O(log S) with O(S) resident heap memory and the queues themselves backed by the store. The database-backed equivalent is a partial index on
(subscription_id, next_attempt_at) where status in ('pending','failed_retryable')claimed withFOR UPDATE SKIP LOCKED, and the write-back must be fenced onlease_tokenso a worker that stalled and resumed cannot overwrite a newer attempt.
Follow-up
- One subscription has 4 million queued deliveries. What stops it from starving the other 199,999, and what does your heap look like under that load?
- A customer requests redelivery of last Tuesday's events. Where do those rows enter your structure, and what keeps them from reordering live traffic?
- The process restarts. How much state do you rebuild, and what stops every subscription from being attempted in the same second?
Seal an hour under late data with bounded memory
Metering ingest reads 256 partitions at 10,000 to 40,000 events/second. Events carry occurred_at and ingested_at, and during a producer replay the gap between them is hours. Seal each UTC hour once no more than 50 parts per million of that hour's eventual quantity can still arrive, using memory that does not grow with the size of the replay. Define the watermark, the lateness parameter and how you measure it, the structure holding open hours, and the write that performs the seal. State what an idle partition does to your watermark.
Approach
- Two clocks, two jobs. Bucket by
occurred_at, because that is the hour the customer is billed for, and advance the watermark oningested_at, because that is what the fold has consumed and whatsource_max_ingested_atrecords. Conflating them is what makes late data invisible. - The global watermark is the min over partitions of each partition's committed
ingested_at, not the max: the fold is trustworthy only as far as the slowest partition. The consequence is that one idle partition pins the watermark forever and nothing seals, so an idle partition must promote its watermark to wall clock after a stated idle timeout, and that timeout becomes a correctness parameter, because a partition that is slow rather than idle gets sealed past. - Choose the lateness L from the measured distribution of
ingested_at - occurred_at, weighted by quantity rather than by event count. The target is 50 ppm of the hour's quantity, and a replay is rare in events while carrying disproportionate mass, so an event-weighted quantile picks an L that is comfortably wrong at exactly the moment it matters. - Measure that quantile in bounded memory. A Greenwald-Khanna summary gives epsilon-approximate quantiles in O((1/epsilon) log(epsilon n)) space; a t-digest costs more per merge but has relative error that tightens at the tails, which is the half of the distribution you are reading at p99.99. Keep a separate summary per tenant class, because one tenant's batch importer is not the population.
- Hold open hours in a min-heap keyed by
hour_start. When the watermark advances, pop every hour withhour_end + L < Wand seal it: O(log H_open) per advance and O(1) amortised per event to touch its bucket. Memory is open hours multiplied by distinct(tenant, workspace, sku)keys, so cap the number of simultaneously open hours and spill the oldest intousage_rollup_hourlyasstatus='open'with arevisionbump. While an hour is open the row is upsertable, so the store is your overflow. - The seal itself is a conditional write:
update ... set status='sealed', sealed_at=now() where status='open' returning .... Two sealers race on every restart, and the loser must see zero rows and stop rather than write a second value. After the seal, an event for that hour is not an upsert but an adjustment, andsource_max_ingested_atis what proves it arrived afterwards.
Follow-up
- A replay starts during the sealing window for a period you are about to close. What do you do, and what is the customer-visible consequence of each option?
- Your measured quantity-weighted p99.99 lateness is six hours and the invoice must be issued at 02:00 UTC on the first. How do you reconcile those two numbers?
- How would you detect that L has drifted before it costs you an hour's quantity?
Find peak concurrent sandbox usage from run intervals
Given up to 5 million job_run rows for one tenant over one day, with run_id, started_at, finished_at, status and wall_clock_limit_seconds, report the maximum number of sandboxes running at once, the earliest instant that maximum is reached, and the first run_id that would breach a per-tenant cap of C. started_at is null while a run is queued; finished_at is null both for runs still executing and for runs in status lost. Treat a run as occupying [started_at, finished_at). Give the complexity and state how you handle each null.
Approach
- Turn each run into two sweep events,
(started_at, +1)and(end, -1), then sort the 2n events by timestamp with-1ordered before+1at equal timestamps. That tie-break is what makes the interval half-open, so a run finishing at 10:00:00 and one starting at 10:00:00 never overlap. - Decide each null out loud before sweeping, because each choice moves the answer. A null
started_atmeans queued and contributes nothing. A nullfinished_atwith statusrunningorleasedis clipped to the window end. Statuslosthas no observed end at all, so clip it atstarted_at + wall_clock_limit_secondson the grounds that the supervisor owns the timeout, and record that you did. The table'scheck (finished_at is null or started_at is not null)guarantees you never see an end without a start. - Sweep once, maintaining a running counter, the maximum, and the timestamp at which the maximum was first attained (update
peak_atonly on a strict increase, or you will report the last such instant instead of the earliest). Capture the firstrun_idwhose+1takes the counter to C+1 during the same sweep rather than in a second pass. - Complexity: O(n log n) dominated by the sort, O(n) space. If rows already arrive ordered by
started_at, a min-heap of end times gives O(n log k) time and O(k) space with k the peak concurrency, which is the better shape when the rows come from an index scan on(tenant_id, started_at). - If second resolution is acceptable, counting-sort the endpoints into an 86,400-slot delta array and prefix-sum it: O(n + T) time and O(T) space, which beats the comparison sort at 5 million rows. It answers only at second granularity, so state which resolution the cap is defined in.
Worked solution 20 min
- Write the null policy as three lines of prose first, one per case, and keep them beside the output.
- Emit 2n endpoint tuples
(timestamp, delta, run_id)and sort on the key(timestamp, delta)so-1precedes+1. - Sweep, tracking
cur,peak,peak_atupdated only on a strict increase, and the firstrun_idwhose+1takescurto C+1. - Build a fixture with two runs where one ends exactly when the next starts, three genuinely overlapping runs, one run with a null
finished_atand statusrunning, and one with statuslostand a 300-secondwall_clock_limit_seconds. - Re-run with every timestamp shifted by a constant and confirm the peak is unchanged while
peak_atshifts by the same constant.
Follow-up
- Now report peak concurrency per tenant for 10,000 tenants from one globally sorted stream. What changes about memory and about the sort?
- The cap has to be enforced at dispatch rather than reported afterwards. What does the admission check look like, and where does it race?
- How would you answer 'peak concurrency within any 5-minute window' without re-sorting?
Explain why the metering dashboard scans every daily partition
usage_event is range-partitioned daily on ingested_at and holds tenant_id, workspace_id, environment, sku, quantity numeric(20,6), occurred_at and ingested_at. The only relevant index is on (occurred_at). A dashboard runs select sku, sum(quantity) from usage_event where tenant_id = $1 and date_trunc('hour', occurred_at) >= $2 and environment = 'production' group by sku, and EXPLAIN shows a sequential scan of every partition. Give each distinct reason, rewrite the predicate so an index can serve it, propose the index, and state the write cost its column order adds.
Approach
- Separate the three causes rather than blaming one. First,
date_trunc('hour', occurred_at)wraps the column, so the predicate is not sargable against a btree on the bare column. Second, pruning keys off ingested_at while the query constrains occurred_at, so no partition can be excluded. Third, even made sargable, (occurred_at) is not tenant-leading, so for one tenant among thousands the scan reads the whole time range and discards nearly all of it. - Rewrite the bound carefully, because the obvious rewrite is only conditionally equivalent.
date_trunc('hour', x) >= $2equalsx >= $2only when $2 is already hour-aligned; for an arbitrary $2 it meansx >= date_trunc('hour', $2) + interval '1 hour'. Normalise the parameter in the caller and leave the column bare. - Restore pruning with a second, redundant predicate on the partition key:
ingested_at >= $2 - interval '<late-data horizon>'. State both sides of it. It prunes to a handful of partitions, and it silently omits any event whose ingest lagged past that horizon, which is precisely what a producer replay produces. Either document the horizon as a stated bound, or partition on occurred_at and move the problem into the dedup window instead. - Propose
(tenant_id, occurred_at) include (sku, quantity)per partition. A partial indexwhere environment = 'production'mostly saves size rather than selectivity, since production dominates the three environments; take it if non-production is a meaningful share and skip it otherwise. - Price the write path honestly. At roughly 250M rows/day each extra index is another insert plus WAL per row, and a tenant-leading key scatters inserts across one hot leaf per active tenant instead of appending to a single rightmost leaf, so page dirtying and random I/O both rise. An INCLUDE payload widens every leaf entry and enlarges the index accordingly.
- Add the index-only-scan caveat before someone reports it as a regression: on a freshly appended table the visibility map is not yet set for recent pages, so the INCLUDE columns still cost heap fetches until autovacuum has been through, and the newest hour is exactly the data the dashboard reads.
Follow-up
- CREATE INDEX CONCURRENTLY is not supported on a partitioned parent. Give the sequence that gets this index onto 400 existing partitions without blocking ingest.
- One tenant holds 200 times the median row count and the dashboard still times out for them with the index in place. What changes?
- Should this read hit
usage_rollup_hourlyinstead? State what that costs in freshness and what the watermark lets you promise.
Enforce a concurrent-run quota that survives simultaneous requests
A plan allows at most 20 concurrently running rows in job_run per tenant. The table holds run_id, tenant_id, workspace_id, status (queued, leased, running, succeeded, failed, timed_out, cancelled, lost), lease_token, leased_until, started_at and finished_at. Today the service runs select count(*) from job_run where tenant_id = $1 and status = 'running', compares the result to 20, then inserts. Under load a tenant exceeds the cap by exactly the number of concurrent requests. Name the anomaly, say which isolation levels do and do not prevent it, and give a version that holds, as SQL.
Approach
- Name it: write skew. Each transaction reads a predicate (the count of running rows), neither modifies what the other read, and both then insert rows that jointly violate an invariant no single row expresses. Read committed permits it. So does repeatable read, because snapshot isolation's first-updater-wins check fires only on conflicting row updates, and these are inserts touching disjoint rows.
- Enumerate the fixes with their real costs. SERIALIZABLE works: PostgreSQL's SSI tracks the predicate read and aborts one transaction with SQLSTATE 40001, which obliges the caller to retry and makes the abort rate rise with contention on a hot tenant. Folding the predicate into the write as
insert ... select ... where (select count(*) ...) < 20narrows the race to the statement's snapshot but does not close it under read committed. - Give the version that holds at read committed: serialise on a row both transactions must touch.
update tenant_concurrency set running = running + 1 where tenant_id = $1 and running < 20 returning runningupdates zero rows when the cap is reached, and zero rows is the rejection. This works because at read committed a blocked UPDATE re-evaluates its WHERE clause against the newly committed row; at repeatable read the same statement raises a serialisation error instead, so the isolation level changes the calling contract. - State the cost you just bought. That row is now a per-tenant serialisation point, so admission throughput for the tenant is bounded by one divided by the lock hold time; at a 2 ms hold that is roughly 500 admissions/second. Keep the critical section to the single UPDATE, with no network call or scheduling decision inside the transaction, and decrement in the same transaction that writes the terminal status.
- Close the leak the status enum implies: a run can end as
lost, so a crashed worker otherwise consumes a slot forever. Reconcile on a schedule againststatus = 'running' and leased_until < now(), and treat the counter as a fast path overjob_run, which stays the system of record.
Worked solution 25 min
- Seed a tenant with 19 running rows, then fire 8 concurrent sessions each running the select-then-insert, and count the resulting running rows.
- Repeat at REPEATABLE READ and confirm the count still exceeds 20.
- Repeat at SERIALIZABLE, count the 40001 aborts, and note that without a retry loop those requests fail rather than queue.
- Implement the atomic counter UPDATE, re-run the 8-way test, and confirm exactly 20 running rows with zero over-admissions.
- Kill a worker mid-run, let the lease expire, and check whether the slot comes back without intervention.
Follow-up
- Write the retry loop for the SERIALIZABLE version. What does the caller see when it keeps aborting, and what bounds the retries?
- Two regions each keep a counter. What is the effective cap, and what does admission do when the counter store is unreachable?
- The cap changes mid-flight on a plan upgrade. Do running jobs get killed, and what does the counter row look like during the change?
How does your background in software engineering align with the goals …
How does your background in software engineering align with the goals of a global mining organization?
Approach
- Work from the requirement backwards to the design.
- Say what you would check first and why it is the highest-information step.
- State your assumptions explicitly before working the problem.
Follow-up
- How would you know your answer was wrong?
- What assumption would you test first?
Why do you want to work for Pan American Silver?
Why do you want to work for Pan American Silver?
Approach
- Work from the requirement backwards to the design.
- Say what you would check first and why it is the highest-information step.
- Clarify what is being asked and what a complete answer contains.
Follow-up
- How would you know your answer was wrong?
- What assumption would you test first?
Can you describe a challenging technical project you managed from star…
Can you describe a challenging technical project you managed from start to finish?
Approach
- Clarify what is being asked and what a complete answer contains.
- State your assumptions explicitly before working the problem.
- Work from the requirement backwards to the design.
Follow-up
- How would you know your answer was wrong?
- What assumption would you test first?
Write the delivery guarantee and replay API for outbound events
The webhook-delivery service fans events to customer endpoints, tracked in webhook_delivery (subscription_id, tenant_id, event_id, redelivery_seq, status, attempt_count, next_attempt_at, lease_token, last_response_code, payload_digest). Customers are asking for exactly-once and in-order delivery. Write the contract you can actually honour: the guarantee, the headers that make it usable, which customer response codes are retryable, the retry schedule and terminal condition, what happens to an endpoint that has been down for a day, and the shape of the redelivery endpoint. State plainly what you are not promising and what the customer must do instead.
Approach
- Refuse exactly-once with the mechanism rather than with policy: the customer's acknowledgement can be lost after they have already committed, so the sender cannot distinguish unprocessed from processed-but-unacknowledged and must retry. The deliverable is at-least-once with a stable event identifier and the customer documented as the deduplicating party.
- Price ordering instead of promising it. With parallel attempts per subscription, a retried event overtakes a newer one, so in-order delivery requires a single in-flight attempt per subscription, which turns any slow endpoint into head-of-line blocking for that subscription's whole queue. Offer it per subscription with that cost written down.
- Define the response contract from the customer's side: 2xx is accepted, 408, 429 and 5xx are retryable, 410 disables the subscription, and every other 4xx is permanent and terminal. Publish the read timeout and tell the customer to acknowledge first and process asynchronously, since their processing time otherwise consumes your worker occupancy.
- Publish the schedule and its end: capped exponential backoff with full jitter, sleeping uniformly in [0, min(cap, base * 2^attempt)] so a mass failure does not re-synchronise the herd, terminal after a stated attempt count or age, plus a per-endpoint circuit breaker that records further deliveries as dropped_circuit_open and notifies the owner rather than burning shared worker capacity.
- Shape redelivery as an insert, not a reset: POST to a redeliveries collection with event ids or a time window creates rows at redelivery_seq + 1 carrying the same bytes, which payload_digest lets you prove, leaving the original terminal rows intact as the record of what happened.
- Compare the event's tenant against the subscription's tenant at enqueue and again immediately before signing, because cross-tenant delivery originates in an enqueue path that took the subscription from one lookup and the payload from another, not in the worker.
Worked solution 30 min
- Write the guarantee sentence and the one-sentence reason exactly-once is not available over HTTP.
- List the headers a customer needs to build their own dedup table: event id, delivery id, attempt number, subscription id, signature and timestamp.
- Write the response-code table with four classes and the action for each, including the 410 case.
- Write the retry schedule with concrete numbers, the terminal condition, and the breaker's threshold and its effect on the delivery row's status.
- Specify the redelivery request and response, and say which columns change and which do not.
Follow-up
- A customer wants everything they missed during their six-hour outage. Do the dropped_circuit_open rows let you answer that, and what retention bound does the answer depend on?
- You offer the ordered mode and one customer's endpoint slows to two seconds per request. What do their delivery metrics look like, and what do you owe them in the docs?
Webhook workers leak until OOM and drop in-flight deliveries
webhook-delivery workers grow from 400 MB to a 2 GB limit over about 36 hours, are OOM-killed, restart, and repeat. Each restart abandons in-flight attempts, so webhook_delivery rows sit in in_flight until their leases expire and the backlog spikes. The live set measured after a forced full collection also grows. The fleet serves tens of thousands of subscriptions, several thousand of which have been failing for weeks. Give an ordered checklist, the measurement separating retention from fragmentation, and the fix.
Approach
- Separate the two failure shapes with one measurement: track resident set size against the live set after a forced full collection. A live set that climbs monotonically is retention; a flat live set under a rising RSS is fragmentation, off-heap or native allocation, or an allocator that never returns pages. The stated symptom puts this in the first category, which rules out allocator tuning as a fix.
- Characterise the curve rather than the total. Growth linear in uptime implies an unbounded structure keyed by something that keeps arriving; step growth implies buffering a large object. Correlate the slope against event rate and separately against the count of distinct subscriptions seen, because those two diverge and only one of them will fit.
- Diff two heap snapshots an hour apart by retained size grouped by dominant root, not by allocation count, which is dominated by short-lived objects and will point at the wrong thing.
- Expect a per-subscription map with no eviction: circuit-breaker or backoff state created on first failure and never removed, so the retained set grows with endpoints that have ever failed, and the several thousand permanently dead endpoints hold theirs forever.
- Fix in two places. Bound the in-memory structure with a size-capped LRU or a TTL keyed on last use, and move state that must survive a restart onto the subscription or webhook_delivery row, since the worker holding it in memory is exactly why a restart loses it.
- Repair the second-order damage separately, because it will outlive the leak: workers claim by compare-and-set with leased_until, so a bounded lease returns in_flight rows to pending on a known schedule, and a graceful shutdown releases leases instead of waiting them out.
Follow-up
- The backlog spike after a restart is itself a thundering herd against customer endpoints. What stops the recovery from becoming a second incident?
- Suppose the live set had been flat while RSS still climbed. Name two causes and the measurement that separates them.
- How would you size the LRU, and what does a miss on an evicted circuit-breaker entry cost a customer whose endpoint is down?
Four days sample coding, design, fundamentals and the practical rounds at deliberately shallow depth, which is enough to surface the topics you did not know were in scope. That map, rather than a guess made on day one, decides where the last three days go.
Prepare, practise & reflect
One practical outcome each day. Spend longer where you need it.
0 / 7 done01Coding, one pass at shallow depth
- Solve one problem from each of six families, an array with two pointers, hash counting, binary search, a tree traversal, a graph traversal and one dynamic program, under a hard twenty-minute cap with no extensions, marking each finished, late, or stalled.
- For every stall, write the exact move you could not make rather than the subject, so the note reads could not turn the recurrence into a loop rather than bad at dynamic programming.
- Fix nothing today. The value of the pass is the unfixed record.
Deliverable: Six timed attempts marked finished, late or stalled, each stall carrying a named blocking move.
Practice prompt ↗Practice prompt ↗Worked solution ↗02Design, one pass at shallow depth
- Spend twenty minutes each on three different shapes, a read-heavy feed, a write-heavy ingest path, and something needing a transaction across two entities, stopping each at requirements, interface and data model.
- After each, write the first question you could not answer, which is usually a number you could not estimate or a failure mode you had no vocabulary for.
- Mark which of the three you would be most relieved not to be asked, and treat that as data rather than as a preference.
Deliverable: Three shallow designs, each with the first unanswerable question written at the bottom.
Practice prompt ↗Practice prompt ↗03Fundamentals and the practical rounds
- Answer eight short questions in writing at four minutes each, covering the material that fills the gaps between the big rounds: what happens between a URL and a rendered page, what an index costs on write, when a process is preferable to a thread, and what conditions a deadlock requires.
- Do one thirty-minute practical task of the kind a take-home compresses: read an unfamiliar two-hundred-line file and write what it does, what you would change, and the one thing you remain unsure of.
- Score every answer fluent, correct but slow, or absent, and keep the absent ones visible.
Deliverable: Eight scored short answers and one written reading of unfamiliar code.
Practice prompt ↗Practice prompt ↗04The rounds that are about you, and the map
- Deliver three behavioural answers aloud against a timer, a conflict, a failure you owned, and a decision made without enough information, marking any that ran past three minutes or contained no number.
- Assemble the map: every marked item from days one to three on a single page, sorted by how likely it is to appear in your loop rather than by how uncomfortable it felt.
- Choose exactly two areas for the remaining three days and write down what you are deliberately abandoning.
Deliverable: A one-page scored map of the whole surface area with two areas chosen and the rest explicitly abandoned.
Practice prompt ↗Practice prompt ↗Worked solution ↗05First chosen area, to the depth you skipped
- Work the higher-ranked area in four focused blocks, choosing items one level above where you stalled rather than repeating what already works.
- After each block write the rule you extracted in one sentence with its precondition attached, since a rule carrying no precondition is exactly what fails under a variation.
- Re-attempt the day-one or day-two item that exposed this area and compare against the original timing.
Deliverable: Four worked blocks, a timed re-attempt against the original, and three one-sentence rules with preconditions.
Practice prompt ↗Practice prompt ↗06Second chosen area, where the gap is coverage rather than speed
- Treat the second area differently from the first. Day five drilled something you could already half-do; this one is usually a topic you had simply never met, so build one worked reference example end to end and keep it, rather than attempting six problems badly.
- Write down the vocabulary you were missing on day two or three, five terms at most, each with the one sentence that makes it usable in an answer rather than the textbook definition.
- Redo the shallow attempt that exposed this area and note whether you now fail later in the problem, because moving the failure point is the realistic gain from a single day and is worth more than a score that did not change.
Deliverable: One worked reference example for the newly covered area, a five-term vocabulary list, and a note on where the failure point moved.
Practice prompt ↗Practice prompt ↗07Reassemble the loop
- Sit two rounds back to back with no gap, ordering them so the area you chose second comes last, because the map was built from rested, isolated attempts and the loop will reach your weaker area when you are already spent.
- Write where the second round suffered from the first, which is normally the point at which structure collapses into narration.
- Reduce the week to one page holding only the rules you can state without reading them.
Deliverable: Mock notes on cross-round carryover plus a one-page card of rules you can recite from memory.
Practice prompt ↗Worked solution ↗Expand any day for tasks and deliverables. Your progress is saved on this device.
A migration is a cost you chose to pay, not an achievement. The story is what the old system made expensive, what you measured before committing, what kept serving traffic during the cutover, and what you would have done if the numbers had come back flat. Without those, a rewrite reads as taste.
What is your strategy for collaborating with non-technical stakeholder…
What is your strategy for collaborating with non-technical stakeholders in an operational environment?
Approach
- Give the blast radius: what could have broken, and what you measured.
- Close with what you would do differently, concretely.
- Pick a story where you made the decision, not one where you watched it.
Follow-up
- How did you know your change caused the improvement?
- What did you decide not to do, and why?
Disclose a cross-tenant webhook delivery to affected customers
An enqueue path took the subscription from one lookup and the payload from another. For nineteen minutes, webhook_delivery rows were created whose tenant_id did not match the subscription's tenant, and eleven payloads were signed and sent to four endpoints belonging to other customers. You hold payload_digest, delivery timestamps and response codes. Describe how you handle a disclosure of this kind: what the records prove, what they cannot prove, what you say before you know everything, the one code change that closes it, and which parts you personally drove.
Approach
- Bound the population before saying anything externally. The affected set is deliveries in the window where the event's tenant and the subscription's tenant differ; the ones that actually left are those with delivered_at set and a 2xx in last_response_code. Attempted and delivered are two different counts and a disclosure has to use the right one in the right sentence.
- Separate what the records prove from what they do not, and say both halves rather than the flattering one. They prove which payloads were signed, where they went, and — through payload_digest — exactly which bytes. They do not prove what the receiving system did with them, and they do not bound the window more precisely than your deploy timestamps do.
- Communicate on the facts you hold, with the scope stated as an upper bound: 'at most eleven payloads, four recipient endpoints, these fields, this window' is more useful and more honest than waiting a day for certainty. The field list matters more than the event count, because a customer cannot assess exposure from 'an event'.
- Name the code change precisely, because this class never originates in the delivery worker. Compare the event's tenant against the subscription's tenant at enqueue and again immediately before the payload is signed, and make the second comparison drop the delivery rather than log a warning. Say why one check is insufficient: the enqueue check protects against the bug you know about, the pre-signing check protects the boundary itself.
- Run the history question in parallel and say so: a query over historical deliveries for the same mismatch tells you whether this was nineteen minutes or a year, and you would rather find the second case yourself than have a customer find it after your disclosure.
- Split the response into workstreams with owners — recipients asked to delete, affected customers notified, the check landed with a test, history swept — and say which you personally drove and which you handed off. Claiming all four is not credible and claiming none is not ownership.
Follow-up
- The historical sweep finds two more instances from last year. What changes in what you have already told people?
- Who approves the wording, and what do you do when you are asked to soften the scope?
- A customer asks you to prove a redelivery contained the same bytes as the original. What do you show them?
Reverse a webhook ordering decision after measuring its cost
You argued for strict per-subscription ordering in webhook-delivery, which means one in-flight attempt per subscription. It shipped. Three months later a single unresponsive endpoint holds one subscription's queue at a six-hour backlog, and two customers report events arriving out of order anyway once their own retries are counted. Describe a decision you reversed: what you originally optimised for, the measurement that changed your mind, what the reversal cost in engineering time and customer change, and how you told the people who had already built on the original guarantee.
Approach
- State the original decision as a trade you made knowingly. Ordering across a network requires a single in-flight attempt per subscription, and its price is head-of-line blocking whenever one endpoint is slow. 'We priced it wrong' is a much stronger opening than 'we did not realise', and it is usually the true one.
- Bring the measurement that flipped it, not the anecdote: backlog age at the ninety-ninth percentile per subscription, the share of subscriptions where one slow endpoint gated an otherwise healthy queue, and the delivery throughput lost to serialisation. A reversal justified by complaints is indistinguishable from a reversal justified by fatigue.
- Name what you learned about the guarantee itself, which is the engineering content of this story. At-least-once delivery means a retried event already arrives after newer ones and the consumer already must be idempotent, so a guarantee the customer has to defend against anyway was never worth what it cost to provide.
- Describe the migration, because reversing a published contract is the hard half and the part candidates skip. Parallel attempts behind a per-subscription flag, a monotonically increasing sequence number added to the envelope so order-sensitive consumers can sort or discard, documentation that states at-least-once and unordered in those words, and a deprecation measured in quarters because the client is a pinned SDK inside a build pipeline you cannot see or redeploy.
- Give the cost in the two currencies that matter: engineer-weeks, and how many customers had to change code. Then say who you told before it shipped rather than in a changelog afterwards, and which large customer you left on the old behaviour and for how long.
- Close with the signal you now weight differently, stated as something you would do earlier next time: measuring the blocking cost on the slowest decile of endpoints before committing to the guarantee, rather than after a customer noticed.
Follow-up
- A customer insists they need ordering. What do you offer them that is not global serialisation?
- How did you choose the deprecation window given that you cannot see or redeploy the clients?
- What would have to be true for you to reverse back?
- 01
What is your strategy for collaborating with non-technical stakeholders in an operational environment?
- 02
An enqueue path took the subscription from one lookup and the payload from another. For nineteen minutes, webhook_delivery rows were created whose tenant_id did not match the subscription's tenant, and eleven payloads were signed and sent to four endpoints belonging to other customers. You hold payload_digest, delivery timestamps and response codes. Describe how you handle a disclosure of this kind: what the records prove, what they cannot prove, what you say before you know everything, the one code change that closes it, and which parts you personally drove.
- 03
You argued for strict per-subscription ordering in webhook-delivery, which means one in-flight attempt per subscription. It shipped. Three months later a single unresponsive endpoint holds one subscription's queue at a six-hour backlog, and two customers report events arriving out of order anyway once their own retries are counted. Describe a decision you reversed: what you originally optimised for, the measurement that changed your mind, what the reversal cost in engineering time and customer change, and how you told the people who had already built on the original guarantee.
Is this an official Pan American Silver interview guide?
No. It is PracHub's own research and practice material for the Software Engineer role at Pan American Silver. Rounds and questions reflect what candidates have reported, not a process Pan American Silver has published, and they change over time. Confirm the current format and scope with your recruiter.
PracHub interview research ↗How long does the hiring process typically take?
Timelines vary based on the specific team and location. Your recruiter can give you an updated timeline during the initial screening.
PracHub interview research ↗What is the most important thing I can do to prepare?
Research Pan American Silver thoroughly. Understanding the company's operations, values, and the specific challenges of the mining industry will set you apart from other candidates.
PracHub interview research ↗Is this role fully remote?
Roles at Pan American Silver often require proximity to the company's operations or corporate offices for collaboration. Please confirm the specific location requirements for your position with your hiring contact.
PracHub interview research ↗What differentiates a strong candidate?
A strong candidate is one who not only demonstrates technical excellence but also shows a genuine interest in Pan American Silver and an ability to work collaboratively with diverse teams.
PracHub interview research ↗Sources & methodology 3 sources ↗
No official company page is cited. Rounds and questions come from candidate reports and PracHub editorial material; each source shows the date it was read.
- 01PracHub interview research ↗
PracHub editorial research into this company and role, maintained with this guide. Candidate-reported, not an employer publication.
PracHub page · Accessed 2026-09-22 - 02PracHub Software Engineer practice ↗
Cross-company practice questions for this role.
PracHub page · Accessed 2026-09-22 - 03PracHub interview preparation framework ↗
The framework the preparation plan follows.
PracHub page · Accessed 2026-09-22
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