Analyze why a linear model can have higher test correlation than training correlation. Then use least-squares geometry to determine what happens when the model is refitted on the former test set.
A linear model is fitted on 70% of a dataset containing 100,000 observations. Its predictions have Pearson correlation 0.20 with the training targets. On the remaining 30%, its predictions have correlation 0.25 with the test targets.
### Clarifying Questions
- Is the fit ordinary least squares with an intercept, using the same feature columns in both subsets?
- Are the correlations empirical correlations between predictions and targets, with nonzero variances?
- Does refitting mean finding the exact unconstrained least-squares solution, without regularization?
For the main argument, use these ordinary least-squares assumptions. Explain which conclusions depend on them.
### Part 1 — Compare Training and Test Correlations
Can the reported 0.20 training correlation and 0.25 test correlation occur? Explain why the larger training sample does or does not determine the ordering.
#### What This Part Should Cover
Separate a typical generalization pattern from a mathematical guarantee about two different samples.
### Part 2 — Refit on the Former Test Set
Fit a new linear model directly on the 30% subset and evaluate its predictions on that same subset. Can its correlation with the targets be below 0.25?
#### What This Part Should Cover
Use the geometry of least squares, distinguish correlation from squared error, and identify assumptions under which the conclusion can fail.
### What a Strong Answer Covers
A precise yes/no answer to each part, a projection argument for the refit, and a clear distinction between evaluation on held-out data and evaluation on the data used for fitting.
### Follow-up Questions
- What changes if the refit uses regularization or a different feature set?
- What if the reported metric is an uncentered similarity instead of Pearson correlation?
Overview: Analyze why a linear model can have higher test correlation than training correlation. Then use least-squares geometry to determine what happens when the model is refitted on the former test set.
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A linear model is fitted on 70% of a dataset containing 100,000 observations. Its predictions have Pearson correlation 0.20 with the training targets. On the remaining 30%, its predictions have correlation 0.25 with the test targets.
Clarifying Questions Guidance
Is the fit ordinary least squares with an intercept, using the same feature columns in both subsets?
Are the correlations empirical correlations between predictions and targets, with nonzero variances?
Does refitting mean finding the exact unconstrained least-squares solution, without regularization?
For the main argument, use these ordinary least-squares assumptions. Explain which conclusions depend on them.
Part 1 — Compare Training and Test Correlations
Can the reported 0.20 training correlation and 0.25 test correlation occur? Explain why the larger training sample does or does not determine the ordering.
What This Part Should Cover Guidance
Separate a typical generalization pattern from a mathematical guarantee about two different samples.
Part 2 — Refit on the Former Test Set
Fit a new linear model directly on the 30% subset and evaluate its predictions on that same subset. Can its correlation with the targets be below 0.25?
What This Part Should Cover Guidance
Use the geometry of least squares, distinguish correlation from squared error, and identify assumptions under which the conclusion can fail.
What a Strong Answer Covers Guidance
A precise yes/no answer to each part, a projection argument for the refit, and a clear distinction between evaluation on held-out data and evaluation on the data used for fitting.
Follow-up Questions Guidance
What changes if the refit uses regularization or a different feature set?
What if the reported metric is an uncentered similarity instead of Pearson correlation?