Locate Cars with a Boolean Square-Scan API

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Define and analyze a car-location search using a Boolean square scanner, with finite-grid subdivision, boundary rules, query cost, and limits on exact coordinates.

Locate Cars with a Boolean Square-Scan API

Company: Applied Intuition

Role: Software Engineer

Category: Software Engineering Fundamentals

Difficulty: medium

Interview Round: Technical Screen

An external scanner exposes this API: ```python def mock_squaredar_scan(lat_min: float, lon_min: float, side_length: float) -> bool: # True if at least one car is inside the queried square; otherwise False. ``` You are asked to design `get_car_positions` using only this Boolean occupancy API. Explain what contract is needed, how a search could work, and what information the API cannot reveal. ### Constraints and Clarifying Questions - Clarify the search region, coordinate system, required precision, boundary inclusion, and whether cars remain stationary during the search. - Ask whether the desired output is exact coordinates, approximate occupied regions, or one result for every car including cars at the same position. - Treat the coordinates as a plane for this practice discussion; no geographic-distance calculation is specified. - Do not assume that a positive square contains exactly one car or that a negative scan says anything about locations outside that square. ### Part 1 — Identify the Missing Contract Explain why the Boolean API alone does not completely specify an exact car-location operation. Identify the conditions needed for a terminating search and a meaningful output. #### What This Part Should Cover - Search coverage, static or snapshot-consistent occupancy, and precision. - The difference between detecting occupancy and counting cars. - Limits on exact recovery from an unbounded or arbitrary-real coordinate domain. ### Part 2 — Design a Conditional Finite-Grid Search For a concrete practice design, suppose the following additional contract is agreed: - All cars are in a known square with lower corner `(x0, y0)` and side length `L`. - The square contains an `N` by `N` grid, where `N = 2^h` for a nonnegative integer `h`, and `delta = L / N`. - Car coordinates are grid points `(x0 + i * delta, y0 + j * delta)` for integer indices `0 <= i, j < N`. - Scans use half-open squares: each lower boundary is included and each upper boundary is excluded. The scanner is exact and reports one unchanged snapshot throughout the search. - Return each occupied grid coordinate once, regardless of how many cars share it. Output order is not significant. Describe a search using the square API. Explain how it handles several cars in different regions, how it terminates, and why it finds every occupied grid position. #### What This Part Should Cover - A subdivision or bisection strategy compatible with square-shaped queries. - Pruning and coverage without assuming that only one child region is occupied. - Correct handling of boundary points and the smallest resolvable region. ### Part 3 — Analyze Cost and Generalize Carefully Analyze the number of scanner calls and working memory. Then explain what the same search can report if cars instead have arbitrary coordinates and `delta` is only a requested spatial resolution. #### What This Part Should Cover - Query cost in terms of grid size and the number of occupied positions. - The distinction between an occupied cell and an exact coordinate. - What remains unknowable about coincident cars or several cars in one final cell. ```hint Interpret a positive answer carefully Consider what one positive scan proves and what it leaves undecided. Check whether several disjoint subregions could all contain cars. ``` ### What a Strong Answer Covers - An explicit contract separating known scanner behavior from added practice assumptions. - A complete conditional search with coverage, termination, and complexity reasoning. - Honest limits on exactness, multiplicity, and changing observations. ### Follow-up Questions - Why is following only one ordinary binary-search branch insufficient when several cars may exist? - What changes if the scanner uses closed boundaries or approximate floating-point comparisons? - Can repeated Boolean scans distinguish one car from several cars at exactly the same coordinate?

Overview: Define and analyze a car-location search using a Boolean square scanner, with finite-grid subdivision, boundary rules, query cost, and limits on exact coordinates.

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Aug 30, 2026
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An external scanner exposes this API:

def mock_squaredar_scan(lat_min: float, lon_min: float, side_length: float) -> bool:
    # True if at least one car is inside the queried square; otherwise False.

You are asked to design get_car_positions using only this Boolean occupancy API. Explain what contract is needed, how a search could work, and what information the API cannot reveal.

Constraints and Clarifying Questions

  • Clarify the search region, coordinate system, required precision, boundary inclusion, and whether cars remain stationary during the search.
  • Ask whether the desired output is exact coordinates, approximate occupied regions, or one result for every car including cars at the same position.
  • Treat the coordinates as a plane for this practice discussion; no geographic-distance calculation is specified.
  • Do not assume that a positive square contains exactly one car or that a negative scan says anything about locations outside that square.

Part 1 — Identify the Missing Contract

Explain why the Boolean API alone does not completely specify an exact car-location operation. Identify the conditions needed for a terminating search and a meaningful output.

What This Part Should Cover Guidance

  • Search coverage, static or snapshot-consistent occupancy, and precision.
  • The difference between detecting occupancy and counting cars.
  • Limits on exact recovery from an unbounded or arbitrary-real coordinate domain.

For a concrete practice design, suppose the following additional contract is agreed:

  • All cars are in a known square with lower corner (x0, y0) and side length L .
  • The square contains an N by N grid, where N = 2^h for a nonnegative integer h , and delta = L / N .
  • Car coordinates are grid points (x0 + i * delta, y0 + j * delta) for integer indices 0 <= i, j < N .
  • Scans use half-open squares: each lower boundary is included and each upper boundary is excluded. The scanner is exact and reports one unchanged snapshot throughout the search.
  • Return each occupied grid coordinate once, regardless of how many cars share it. Output order is not significant.

Describe a search using the square API. Explain how it handles several cars in different regions, how it terminates, and why it finds every occupied grid position.

What This Part Should Cover Guidance

  • A subdivision or bisection strategy compatible with square-shaped queries.
  • Pruning and coverage without assuming that only one child region is occupied.
  • Correct handling of boundary points and the smallest resolvable region.

Part 3 — Analyze Cost and Generalize Carefully

Analyze the number of scanner calls and working memory. Then explain what the same search can report if cars instead have arbitrary coordinates and delta is only a requested spatial resolution.

What This Part Should Cover Guidance

  • Query cost in terms of grid size and the number of occupied positions.
  • The distinction between an occupied cell and an exact coordinate.
  • What remains unknowable about coincident cars or several cars in one final cell.

What a Strong Answer Covers Guidance

  • An explicit contract separating known scanner behavior from added practice assumptions.
  • A complete conditional search with coverage, termination, and complexity reasoning.
  • Honest limits on exactness, multiplicity, and changing observations.

Follow-up Questions Guidance

  • Why is following only one ordinary binary-search branch insufficient when several cars may exist?
  • What changes if the scanner uses closed boundaries or approximate floating-point comparisons?
  • Can repeated Boolean scans distinguish one car from several cars at exactly the same coordinate?
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