Solve three independent probability questions. Explain the assumptions and derivation clearly, check edge cases, and show how the result changes when those assumptions no longer hold.
# Solve Three Probability Models
Solve three independent probability questions. Show the sample space or stochastic assumptions in each part and give an exact result.
### Constraints & Assumptions
- Every die roll is independent and uniformly distributed from 1 through 6.
- In the meeting problem, each person arrives independently and uniformly during a 60-minute interval and waits at most 15 minutes.
- In the traffic problem, vehicle arrivals follow a homogeneous Poisson process with independent increments.
### Clarifying Questions to Ask
- In the die game, is the payoff the face on the final accepted roll rather than the sum?
- Does a meeting occur when one person arrives exactly 15 minutes after the other?
- Is the one-hour traffic probability assumed stationary across both half-hours?
### Part 1 — Three-Roll Optimal Stopping
You may roll a fair die at most three times. After each roll you may stop and receive that face value; if you continue, the previous face is discarded. Compute the optimal policy and expected payoff.
#### What This Part Should Cover
- Backward induction and the acceptance threshold on each remaining decision.
- An exact expected value, including tie behavior.
### Part 2 — Two People Meeting
Two people arrive independently during one hour and each waits 15 minutes. Compute the probability that they meet.
#### What This Part Should Cover
- A geometric sample space and the complement formed by two corner triangles.
- Correct scaling of 15 minutes to one quarter of the hour.
### Part 3 — Poisson Half-Hour Probability
The probability of at least one vehicle in an hour is 0.96. Compute the probability of at least one vehicle in half an hour.
#### What This Part Should Cover
- Use of the no-arrival complement and independent equal-length increments.
- A result derived without first needing the explicit rate parameter.
```hint Work backward on the die
The value of rejecting a roll is the expected value of the game with one fewer roll remaining.
```
```hint Draw the arrival square
Meeting corresponds to points within distance one quarter of the diagonal line.
```
### What a Strong Answer Covers
- Exact probability reasoning, clearly stated independence assumptions, and checks that every result lies in its feasible range.
### Follow-up Questions
- How does the die policy change with N allowed rolls?
- What is the meeting probability when the two waiting times differ?
Quick Answer: Solve three independent probability questions. Explain the assumptions and derivation clearly, check edge cases, and show how the result changes when those assumptions no longer hold.
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Solve Three Probability Models
Solve three independent probability questions. Show the sample space or stochastic assumptions in each part and give an exact result.
Constraints & Assumptions
Every die roll is independent and uniformly distributed from 1 through 6.
In the meeting problem, each person arrives independently and uniformly during a 60-minute interval and waits at most 15 minutes.
In the traffic problem, vehicle arrivals follow a homogeneous Poisson process with independent increments.
Clarifying Questions to Ask Guidance
In the die game, is the payoff the face on the final accepted roll rather than the sum?
Does a meeting occur when one person arrives exactly 15 minutes after the other?
Is the one-hour traffic probability assumed stationary across both half-hours?
Part 1 — Three-Roll Optimal Stopping
You may roll a fair die at most three times. After each roll you may stop and receive that face value; if you continue, the previous face is discarded. Compute the optimal policy and expected payoff.
What This Part Should Cover Guidance
Backward induction and the acceptance threshold on each remaining decision.
An exact expected value, including tie behavior.
Part 2 — Two People Meeting
Two people arrive independently during one hour and each waits 15 minutes. Compute the probability that they meet.
What This Part Should Cover Guidance
A geometric sample space and the complement formed by two corner triangles.
Correct scaling of 15 minutes to one quarter of the hour.
Part 3 — Poisson Half-Hour Probability
The probability of at least one vehicle in an hour is 0.96. Compute the probability of at least one vehicle in half an hour.
What This Part Should Cover Guidance
Use of the no-arrival complement and independent equal-length increments.
A result derived without first needing the explicit rate parameter.
What a Strong Answer Covers Guidance
Exact probability reasoning, clearly stated independence assumptions, and checks that every result lies in its feasible range.
Follow-up Questions Guidance
How does the die policy change with N allowed rolls?
What is the meeting probability when the two waiting times differ?