A verbal algorithm question about a dating app with P users and a constant-time match score: find the N best matches for one user when N is much smaller than P. It tests choosing a data structure that avoids sorting everyone and analyzing the resulting time and space complexity.
Top N Matches Among P Dating-App Users Given an O(1) Match Function
Company: Duolingo
Role: Software Engineer
Category: Software Engineering Fundamentals
Difficulty: easy
Interview Round: Technical Screen
A dating app has $P$ users. A function `get_match(a, b)` returns a numeric match score for users `a` and `b` in $O(1)$ time; a higher score means a better match. For a given user, find the $N$ best matches among the other users, where $N$ is much smaller than $P$.
Describe your approach and give its time and space complexity. This was a verbal question: explain the approach rather than writing full code.
```hint You never need the full ranking
Only the best $N$ matter. Think about what you must remember about the candidates seen so far, and how cheaply you can decide whether a new candidate gets in.
```
### Clarifying Questions
- Should the result be ordered from best to worst match?
- How should ties in score be broken?
- What if there are fewer than $N$ other users?
- Is this a one-off query for one user, or will it run for every user?
### What a Strong Answer Covers
- A correct baseline (score everyone and sort) and why it does more work than needed when $N \ll P$
- A structure that keeps only the current best $N$ candidates and decides cheaply whether a new candidate belongs
- Time complexity in terms of both $P$ and $N$, and space complexity
- At least one alternative, such as selection, with its trade-offs
- Edge cases: excluding the user themselves, ties, fewer than $N$ candidates
### Follow-up Questions
- Match lists must be computed for every user every night. How does the total cost grow with $P$, and what would you change?
- The user list is too large to fit in memory and arrives as a stream. Does your approach still work?
- The users are split across several machines. How do you combine partial results into the global best $N$?
Overview: A verbal algorithm question about a dating app with P users and a constant-time match score: find the N best matches for one user when N is much smaller than P. It tests choosing a data structure that avoids sorting everyone and analyzing the resulting time and space complexity.
A dating app has P users. A function get_match(a, b) returns a numeric match score for users a and b in O(1) time; a higher score means a better match. For a given user, find the N best matches among the other users, where N is much smaller than P.
Describe your approach and give its time and space complexity. This was a verbal question: explain the approach rather than writing full code.
Clarifying Questions Guidance
Should the result be ordered from best to worst match?
How should ties in score be broken?
What if there are fewer than
N
other users?
Is this a one-off query for one user, or will it run for every user?
What a Strong Answer Covers Guidance
A correct baseline (score everyone and sort) and why it does more work than needed when
N≪P
A structure that keeps only the current best
N
candidates and decides cheaply whether a new candidate belongs
Time complexity in terms of both
P
and
N
, and space complexity
At least one alternative, such as selection, with its trade-offs
Edge cases: excluding the user themselves, ties, fewer than
N
candidates
Follow-up Questions Guidance
Match lists must be computed for every user every night. How does the total cost grow with
P
, and what would you change?
The user list is too large to fit in memory and arrives as a stream. Does your approach still work?
The users are split across several machines. How do you combine partial results into the global best
N
?